2 years ago

Write the equations for the lines parallel and perpendicular to the given line j that passes through Q.

Mathematics

1 answer:

Anna007 [38]2 years ago

3 0

Answer:

the third option

i think this is right but I could be wrong, sorry.

You might be interested in

after selling tickets to a dance for $3.25 each, the student council brought in $1020.50from tocket sales. how many tickets did

balu736 [363]

3.25x = 1020.50

/3.25 /3.25

x = 314 tickets sold.

7 0

2 years ago

HELP!!! i need the remainder as well!

denis23 [38]

ABC = 54 feet squared

7 0

2 years ago

HELP ME PLEASE ASAP

sleet_krkn [62]

D :- 10 - 25 = -5

4 - 5 = -1

Required Answer:- -1

5 0

2 years ago

Read 2 more answers

Which expression represnts the product of 2xy and 3xy+5y-xy^2

melisa1 [442]

Answer:

You distribute the 2xy and get

2xy(3xy + 5y - xy^2) = 6(x^2)(y^2) + 10xy^2 - 2(x^2)(y^3)

8 0

2 years ago

When fritz drives to work his trip takes 40 minutes, but when he takes the train it takes 30 minutes. find the distance fritz t

sweet-ann [11.9K]

Distance = rate*time

convert minutes to hour first because the question talking about 15 mile per hour
40 mins = 40/60 2/3 hrs
30 mins = 30/60 = 1/2hrs

Assume that s be the speed when Fritz driving, so
s + 15 will be the speed of the train.

We know the time we know the speed, Next
distance that Fritz drive = $\frac{2}{3}s$
distance the train travel = $\frac{1}{2}(s+15)$

The question: Assume that the train travels the same distance as the car
==> $\frac{2}{3}s = \frac{1}{2}(s+15)$
==> $\frac{2}{3}s = \frac{1}{2}s + \frac{15}{2}$
==> $\frac{2}{3}s - \frac{1}{2}s = \frac{15}{2}$
==> $\frac{1}{6}s = \frac{15}{2}$
==> $\frac{6}{1} * \frac{1}{6}s = \frac{15}{2} * \frac{6}{1}$
==> $s = 45$
Now we know that Fritz drive at 45 mph,
distance = $\frac{2}{3} * 45 = 30 miles$

3 0

3 years ago