6(5r-11)-(5-r)}6(5r−11)−(5−r)
2 answers:
You might be interested in
Answer:
<em>The answer is</em> <em>{-(5)
(36)×
-(180)</em>
Step-by-step explanation:
A polynomial with rational coefficients has roots 5 and -6i (There i is the
imaginary number not variable )
As we knew that imaginary no comes in pair . This means that if -6i is
one root then the other root will be 6i
So if we assume the lowest polynomial that is possible is given as
{-(sum of all roots)
+(roots taken two at a time)
-(product of all roots)
{-(5+6i+(-6i))
+(5×6i +5×(-6i) +6i×(-6i))
-(5×6i×(-6i))
= -1
<em>{-(5)
(36)×
-(180)</em>
<em> </em>The <u>general case</u> we assume that the three previous roots and rest roots
a4,a5,a6 ...............an
-(sum of all roots)×
+(roots taken two at a
time) ×- .......................................... (product of all roots)