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3 years ago

The "given" information should be considered as true. True False

1 answer:

8 0

Unless refuted later in the equation, this statement would be True because they are normally giving you the data to work with to save you the time of finding it yourself.

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What is 3n+2n simplified

Ber [7]

The answer for this is n(3+2)

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3 years ago

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4[(10-4) 2 to the second power divided by 4]

SashulF [63]

4[(10-4) 2 to the second power divided by 4]
=4x6x2 to the second power divided by 4
=6x2 to the second power
=6x4
=24
Hope that helps and hope that I didn't misunderstand your question

4 0

3 years ago

Will mark brainliest meed asap ! Question 1 Solve – 3 = -12 using inverse operations

Brrunno [24]

Answer:

Step-by-step explanation:

First, she has to add. Second, she has to divide.

5x - 3 = 12

+ 3 + 3

——————

5x = 15

x = 3

Hope this helps!

6 0

2 years ago

Read 2 more answers

The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l

mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: $(\frac{n+1}{2}) th\ term$

Putting n=21

$(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term$

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

For First Half:

98, 100, 101, 102, 108, 109, 111,118, 129, 132

$Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5$

For Second Half:

135, 135, 145, 146, 146, 156, 170 176, 180, 180

$Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151$

Now

Interquartile Range:

$IQR = Q_3-Q_1\\= 151-108.5\\=42.5$

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

#LearnwithBrianly

7 0

3 years ago

Help me plz!! I need help and NO FILES PLZZZZZZZ!

Solnce55 [7]

Answer:

EXPLAINATION:

y = mx +b

b = y intercept

4 0

3 years ago