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4 years ago

Which expression is equivalent to (3 / x − 2) − 5 / 2 − (4 / x − 2) ?

Mathematics

2 answers:

Dominik [7]4 years ago

5 0

Yo download photos math in take a pic of your problem in it would give you your answer

ivolga24 [154]4 years ago

3 0

Answer: d

Step-by-step explanation:

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if Andy's home is worth 260,000, what is his coverage for personal property if insurance covers 50 percent?

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3 years ago

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I need help on this question

spin [16.1K]

Answer:

c. 24/25

Step-by-step explanation:

1. Use SOH CAH TOA

2. Highlight C, so you know what your looking for

3. Since were finding the cosine of C we need the side adjacent(next to) and the hypotenuse of C. We know this because of CAH(cosine= adjacent/hypotenuse

4. C is closest to 24 so we have our adjacent side as 24, this will be the numerator

5. Then find the hypotenuse, which is opposite of the 90 degree angle, marked by the square box in the triangle

6. Our Hypotenuse is 25, which will be our denominator

<h3>7. Giving the answer is 24/25</h3>

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3 years ago

(−4)+(−6)+(−3)+(−1)+0+2+(−1)+(−3)8

andrezito [222]

Answer:

-15

Step-by-step explanation:

Multiply: (-3)8= -24

Add: -4+6+3+1+0+2+1= 9

Subtract: 9-24= -15

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2 years ago

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Simplify this equation please.

Sauron [17]

$\dfrac{\csc^2\theta-3\csc\theta+2}{\csc^2\theta-1}$

Identity:

$\sin^2\theta+\cos^2\theta=1\implies1+\cot^2\theta=\csc^2\theta$

So we can rewrite the denominator to get

$\dfrac{\csc^2\theta-3\csc\theta+2}{\cot^2\theta}$

Multiply numerator and denominator by $\sin^2\theta$ . Several terms will cancel since $\sin\theta\csc\theta=1$ . Also, $\cot\theta=\dfrac{\cos\theta}{\sin\theta}$ . We get

$\dfrac{1-3\sin\theta+2\sin^2\theta}{\cos^2\theta}$

Factorize the numerator, and write $\cos$ in terms of $\sin$ in the denominator to factorize it further to get

$\dfrac{(1-\sin\theta)(1-2\sin\theta)}{\cos^2\theta}=\dfrac{(1-\sin\theta)(1-2\sin\theta)}{1-\sin^2\theta}=\dfrac{(1-\sin\theta)(1-2\sin\theta)}{(1-\sin\theta)(1+\sin\theta)}$

The $1-\sin\theta$ factors cancel, leaving you with

$\dfrac{1-2\sin\theta}{1+\sin\theta}$

which you could simplify a bit further by writing

$\dfrac{1+\sin\theta-3\sin\theta}{1+\sin\theta}=1-\dfrac{3\sin\theta}{1+\sin\theta}$

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4 years ago