Answer:
How much will a 60 affect my grade?
If it is a test grade, which in my school they are worth 60%, then it will bring you down by pretty much a whole lot, probably about 7–10 points. If it is a 20% weight it will only bring it down by about 2–3 points.
Step-by-step explanation:
Answer: |p-72% |≤ 4%
Step-by-step explanation:
Let p be the population proportion.
The absolute inequality about p using an absolute value inequality.:
, where E = margin of error, 
= sample proportion
Given: A poll result of 72% with a margin of error of 4% indicates that p is most likely to be between 68% and 76% .
|p-72% |≤ 4%
⇒ 72% - 4% ≤ p ≤ 72% +4%
⇒ 68% ≤ p ≤ 76%.
i.e. p is most likely to be between 68% and 76% (.
The x - intercept is 
and y - intercept is (0, 5)
<h3><u>Solution:</u></h3>
Given that : 3x + y = 5
<em><u>To find: x - intercept and y -intercept</u></em>
The x-intercept is where a line crosses the x-axis, and the y-intercept is the point where the line crosses the y-axis.
To find the x intercept using the equation of the line, plug in 0 for the y variable and solve for x
3x + 0 = 5
3x = 5
Therefore the x - intercept is
To find the y intercept using the equation of the line, plug in 0 for the x variable and solve for y
3(0) + y = 5
y = 5
Therefore y - intercept is (0, 5)
Answer:
The marginal-cost function is;
c'(x)= (20x-1)/(2√(400 + 10x² - x))
Completed question;
The cost of producing x bags of dog food is given by C(x) = 800 + √(400 + 10x² - x) where 0≤x≤55000. Find the marginal-cost function.
The marginal-cost function is c'(x)=
(Use integers or fractions for any numbers in the expression.)
Step-by-step explanation:
The marginal-cost function is c'(x)= = dC(x)/dx
Where;
C(x) = 800 + √(400 + 10x² - x)
c'(x) = d(800 + √(400 + 10x² - x) )/dx
Using function of function rule of differentiation or chain rule;
c'(x) = (20x-1)×(1/2√(400 + 10x² - x))
c'(x) = (20x-1)/(2√(400 + 10x² - x))
The marginal-cost function is;
c'(x)= (20x-1)/(2√(400 + 10x² - x))
Hi there!
You need to prove that line segment DE ≅ GH.
You're given:
Line segment DJ ≅ line segment GJ;
E is the midpoint of line segment DF;
H is the midpoint of line segment GJ.
You can justify that line segment DE ≅ line segment GH with the midpoint definition, which is a point on a line segment that divides it into two equal parts. The two equal parts in this case are line segments DE and GH, so DE ≅ GH.
Please comment with <em></em>any questions!
