<span>In a jar of ten beads; since 3 are blue; probability of picking a blue ball, B, = p(b) = 3/10. And P (of not picking a blue ball) ; p(b') = 7/10.
Since it occurs with replacement, probabilities doesn't change
Probaility of picking k blue balls from on n attempts is given by P_n(k)
P_n(k) = (n, k) p^(k) q^(n -k) where p and q are b and b' respectively.
P_5(2) = (5 , 2) (0.3)^(2) (0.7)^(5 - 2)
P_5(2) = 5C2 (0.3)^(2) (0.7)^(3) = 0.3087</span>
3.14((4^2)+(4)(2))
3.14(16+8)
3.14(24)
=75.36
You just want to plug in the values of a and b into the equation and solve using order of operations. Hope this helps!
Answer:
The answer is 0.0096
Step-by-step explanation:
which is 0.00032 multiplyed by 30
Answer:
9*100+7*10+2*1
Step-by-step explanation:
hope you like it
Answer:
x = 6
Step-by-step explanation:
