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Ne4ueva [31]
3 years ago
8

The equation of line k is y = -6/7 x + 10. Line m is perpendicular to line k and passes through (-3, -5). What is the equation o

f line m?
Write the equation in slope-intercept form. Write the numbers in the equation as proper fractions, improper fractions, or integers
Mathematics
2 answers:
lara31 [8.8K]3 years ago
7 0
Convert -6/7 to 7/6 because they have to multiply together to equal -1.

Plug the -3 into x and the -5 into y

-5=7/6(-3)+b
(y=mx+b format)

-5=-3.5+b

Add 3.5 to both sides.

-1.5=b

Now add to the equation we had at the top to get your answer.

y=7/6x-1.5
Akimi4 [234]3 years ago
6 0

Answer:

SOMEONE HURRY AND ANSWER THIS

Step-by-step explanation:

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Find the value of 4³
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Step-by-step explanation:

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3 0
3 years ago
each of exercises 15–30 gives a function ƒ(x) and numbers l, c, and e 7 0. in each case, find an open interval about c on which
3241004551 [841]

The given inequality holds for the open interval (2.97,3.03)

It is given that

f(x)=6x+7

cL=25

c=3

ε=0.18

We have,

|f(x)−L| = |6x+7−25|

          = |6x−18|

          = |6(x−3)|

          = 6|x−3|

Now,

6|x−3| <0.18  then |x−3|<0.03 ----->−0.03<x-3<0.03---->2.97<x<3.03

the given inequality holds for the open interval (2.97,3.03)

For more information on inequality click on the link below:

brainly.com/question/11613554

#SPJ4

Although part of your question is missing, you might be referring to this full question: For the given function f(x) and values of L,c, and ϵ0, find the largest open interval about c on which the inequality |f(x)−L|<ϵ holds. Then determine the largest value for δ>0 such that 0<|x−c|<δ→|f(x)−|<ϵ.

f(x)=6x+7,L=25,c=3,ϵ=0.18

 

.

6 0
2 years ago
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