2's and 3's of GCF
HOpe iT hElpeED I'M cOOl
5+4v-v=1+3+5v
5+3v=4+5v
minus 3v both sides
5+3v-3v=4+5v-3v
5+0=4+2v
5=4+2v
minus 4 both sides
5-4=4-4+2v
1=0+2v
1=2v
divide both sides by 2
1/2=v
<span>3p - 6 > 21 <=> 3p > 21+6 <=> 3p > 27 <=> p > 27/3 <=> p > 9. So the answer is B. When solving inequalities the idea is to move the terms which contain the unknown quantity to one side and the rest of the terms to the other side. And then perform valid mathematical operations to find the interval value for the unknown quantity.</span>
Answer:
circle on 1 and all numbers to the right shaded closed circle on 1 and all numbers to the left shaded
Step-by-step explanation: