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OlgaM077 [116]
3 years ago
9

A 4-meter ladder is placed against a wall so

Mathematics
1 answer:
krek1111 [17]3 years ago
8 0

Answer:

1.5 meters.

Step-by-step explanation:

The ladder is 4 meters.

It reaches the height of 3.7 meters on a wall.

This creates a right angled triangle of hypotenuse (4 meters) and height (3.7 meters).

We are to find the base length.

Applying the Pythagorean theorem;

a² + b² = c² , where a is the base length, b is the height length and c is the hypotenuse length.

∴ a² = c² - b² = 4² - 3.7² = 2.31

a (base length) = \sqrt{2.31} = 1.519868415 meters

To round off the answer to the nearest tenth of a meter;

Tenth of a meter = \frac{1}{10} × 1 meter = 0.1 meters

So we're rounding off the answer to one decimal place.

I.e 1.519868415 meters = 1.5 meters (rounded off to the nearest tenth of a meter.

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The solution to the differential equation y'(y + 7)y'' = (y')²

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Step-by-step explanation:

Given the differential equation

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We want to solve using the substitution u = y'.

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