Answer:
The code to this question as follows:
Code:
if(x < y) //if block that check value of x less then value of y
{
if(x<z) // inner if block that check value of x less then value of z
{
min = x; //assign value of x in min variable
}
else // inner else block when condition is false
{
min = z; //assign value of z in min variable
}
}
else //outer else block
{
if(y<z) //if block to check value of variable y is less then value of z
{
min = y; //assign value of y in min variable
}
else //else block
{
min = z; //assign value of z in min variable
}
}
Explanation:
In the given question it is defined, that an integer variable " x, y,z, and min" is declared, in which variable "x,y, and z" value is defined, and the variable is used to assign a big value.
- To check the biggest value we use the if-else statement in which, and if block check value of x is less than then the value of y if this condition is true so, inside this another if block declares, that will check if the value of x is less then z. if this is true, it will assign the value of x in min variable else it will assign the value of z in min.
- In the outer else part, another conditional block has used, that checks if the value of y is less than then the value of z if it is true, it assigns the value of y in min else it will assign the value of z in min.
The recursive function divBy3And5 is defined in Python and is found in the attached image.
In the base case, the function divBy3And5 tests if the input list is empty. If so, the tuple returned is . This means no numbers are divisible by three and no numbers are divisible by five.
The recursive step gets the first element of the list and
- If divisible by 3, it sets <em>count_of_3</em> to 1, else it leaves it as 0
- If divisible by 5, it sets <em>count_of_5</em> to 1, else it leaves it as 0
It then makes a recursive call on the remaining elements, and stores it in a variable as follows
<em>divBy3And5_for_remaining_elem</em> = divBy3And5(remaining_elements)
Then, it returns the tuple
(<em>divBy3And5_for_remaining_elem</em>[0] + <em>count_of_3</em>,
<em>divBy3And5_for_remaining_elem</em>[1] + <em>count_of_5)</em>
Learn more about recursion in Python: brainly.com/question/19295093
In the CSS, background-image: url( "/path/to/file" )
http://www.w3schools.com is a handy reference.
Answer:
date allow you to see what the final web
Explanation:
because data is common media of an