Step-by-step explanation:
Pathagory and Theorem
a^2+b^2=c^2
(x-3)^2+(x-4)^2=6^2
expand:
2x^2-14x+25=36
2x^2-14x-11=0
x=(\sqrt{71}+7)/2
perimeter=(x-3)+(x-4)+6=2x-1
insert the value for x into 2x-1
+6=perimeter
Hope that helps :)
Answer BOTH questions please!
1 answer:
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