+(7p-8q+6pq)+(q-2p+pq)-(10pq-p-4q)
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9514 1404 393
Answer:
D 2.14
Step-by-step explanation:
The lengths of interest are the hypotenuses of the respective triangles. We are given the angle and the opposite side, so the sine relation is of interest.
Sin = Opposite/Hypotenuse
sin(34°) = AC/AB ⇒ AB = AC/sin(34°)
sin(53°) = AC/AD ⇒ AD = AC/sin(53°)
The desired difference in lengths is ...
AB -AD = AC(1/sin(34°) -1/sin(53°)) = 4(1.78829 -1.25214) ≈ 2.1446
The difference in lengths is about 2.14 units.
