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bixtya [17]
3 years ago
11

The state of Connecticut has an opening on a three-member board that settles labor disputes between unions and employers. Which

applicant is best qualified for the position?
A. Rebecca, a thorough Law Clerk who is known for her organizational and time management skills in the courtroom
B. Charlie, a quick-thinking Lawyer who is known for his power of persuasion and his knowledge of laws and procedures C. Sonia, an experienced Mediator who is known for her reasoning and skills in communicating and negotiating
D. Tom, a talented Paralegal who is known for his ability to research and accurately prepare legal documents​

SAT
2 answers:
konstantin123 [22]3 years ago
6 0

Answer:

correct answer is c

Explanation:

got it right on edge

kolezko [41]3 years ago
4 0

Answer:

B

Explanation:

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What is the conjugate of -2+3i
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Explanation:

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2 years ago
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In a recent year, about 22% of Americans 18 years and older are single. What is the probability that in a random sample of 200 A
Pie

Using the normal approximation to the binomial, it is found that there is a 0.0107 = 1.07% probability that more than 30 are single.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with \mu = np, \sigma = \sqrt{np(1-p)}.

In this problem, the proportion and the sample size are, respectively, p = 0.22 and n = 200, hence:

\mu = np = 200(0.22) = 44

\sigma = \sqrt{np(1 - p)} = \sqrt{200(0.22)(0.78)} = 5.8583

The probability that more than 30 are single, using continuity correction, is P(X > 30.5), which is <u>1 subtracted by the p-value of Z when X = 30.5</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{30.5 - 44}{5.8583}

Z = -2.3

Z = -2.3 has a p-value of 0.0107.

0.0107 = 1.07% probability that more than 30 are single.

More can be learned about the normal distribution at brainly.com/question/24663213

6 0
2 years ago
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