2 years ago

I need help in this please

SAT

1 answer:

IgorC [24]2 years ago

5 0

Answer:

customer and consumer

Explanation:

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At a large corporation, the distribution of years of employment for the employees has mean 20.6 years and standard deviation 5.3

Cerrena [4.2K]

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Yes

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The z score is a score used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

$z=\frac{x-\mu}{\sigma}\\\\where\ \mu=mean.\sigma=standard\ deviation, x=raw\ score.\\\\For\ a \ sample\ size\ n:\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }$

For a normal distribution with a mean of μ and standard deviation σ, For any sample size (n) drawn from this population, the sample mean is normally distributed, with mean $\mu_x=\mu$ and standard deviation $\sigma_x=\frac{\sigma}{\sqrt{n } } \\\\$ .

Hence given that a mean of μ = 20.6 years and standard deviation σ = 5.3 years, for a sample size of 100:

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