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worty [1.4K]
4 years ago
11

____2. Find the value of x A 16 C 50 B 34 D 70

Mathematics
1 answer:
olga2289 [7]4 years ago
6 0
50.........................
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Laws of indices please solve
lorasvet [3.4K]

Answer:

here ,

\sqrt[3]{x {}^{3} y {}^{3}  }

= (x {}^{3} y {}^{3} ) {}^{ \frac{1}{3} }

therefore the anwer is xy.

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Unit rate is the thing that describes y and x
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At Glenridge High School, 20 percent of the
Makovka662 [10]

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40 percent

Step-by-step explanation:

60 - 20 = 40

Reasoning: The amount of seniors that attended was 20 percent, so 60 (total students) percent minus 20 percent is equal to 40 percent.

Hope this helps!

3 0
3 years ago
Employees from A and company B receive annual bonuses. What information would you need to test the claim that the difference in
lyudmila [28]

Answer:

1. The required information are

The average annual bonuses, \bar {x}_1 received by employees from company A

The average annual bonuses, \bar {x}_2 received by employees from company B

The standard deviation, σ₁, of the average annual bonuses for employees from company A

The standard deviation, σ₂, of the average annual bonuses for employees from company A

The number of employees in company A, n₁

The number of employees in company B, n₂

2. The null hypothesis is H₀: \bar {x}_1 - \bar {x}_2 ≤ 100

The alternative hypothesis is Hₐ: \bar {x}_1 - \bar {x}_2 > 100

Step-by-step explanation:

1. The required information are

The average annual bonuses, \bar {x}_1 received by employees from company A

The average annual bonuses, \bar {x}_2 received by employees from company B

The standard deviation, σ₁, of the average annual bonuses for employees from company A

The standard deviation, σ₂, of the average annual bonuses for employees from company A

The number of employees in company A, n₁

The number of employees in company B, n₂

2. The null hypothesis is H₀: \bar {x}_1 - \bar {x}_2 ≤ 100

The alternative hypothesis is Hₐ: \bar {x}_1 - \bar {x}_2 > 100

The z value for the hypothesis testing of the difference between two means is given as follows;

z=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}

At 0.5 level of significance, the critical z_\alpha = ± 0

The rejection region is z > z_\alpha and z < -z_\alpha

Therefore, the value of z obtained from the relation above more than or less than 0, we reject the null hypothesis, and we fail to reject the alternative hypothesis.

7 0
3 years ago
HELPPPP ASAPPPP PLSSS
lozanna [386]

Answer:

what dose the top say I can help after that if that works for you

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