There are 123 Asians, 25 Africans, 21 Europeans and 8 Americans in the village.
To determine the number of Asians, Africans, Europeans, and Americans in the village, the following calculation must be performed:
- A.S + A.F + E.U + A.M = 177
- A.S = A.F + E.U + 69
- E.U - A.M = 13
- E.U = A.M + 13
- 2A.F = E.U + A.M + 29
- A.F + E.U + 69 + A.F + E.U + A.M = 177
- A.F + A.M + 13 + 69 + A.F + A.M + 13 + A.M = 177
- 2A.F + 3A.M = 177 - 13 - 13 - 69
- E.U + A.M + 29 + 3A.M = 82
- A.M + 13 + A.M + 29 + 3A.M = 82
- 5A.M = 82 - 13 - 29
- A.M = 40/5
- A.M = 8
- E.U = 8 + 13 = 21
- A.F = (21 + 29) / 2 = 25
- A.S = 177 - 25 - 21 - 8 = 123
Therefore, there are 123 Asians, 25 Africans, 21 Europeans and 8 Americans in the village.
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Answer:
Step-by-step explanation:
Given
Required
Convert to fraction
To do this, we simply multiply the fraction by 100%
This gives:
The expression cannot be further simplified.
Take for instance the fraction is: 
Using the same analysis, the percentage would be:
Answer:
2 animals
Step-by-step explanation:
Number of animals=40
Fraction of fish=3/4
=>number of fish=3/4*40=30
Fraction of cats=1/5
=>number of cats=1/5*40=8
Animals which are not cats or fish are=total number of animals-(number of cats + number of fish)
Animals which are not cats or fish=40-(8+30)
40-38
2 animals
C as anything greater than -4 wouldn't be included within the solution set
This formula is used to find the median in a group data which is located in the median class. Median, m = L + [ (N/2 – F) / f ]C
L means lower boundary of the median class N means sum of frequencies F means cumulative frequency before the median class.
Hope this helps :))
