<span>
The probability of at least three heads can be found by<span><span>∑<span>k=3</span>4</span><span>(<span>4k</span>)</span><span>.5k</span><span>.5<span>4−k</span></span>=<span>516</span></span></span>
0.0003 would be 1/10 of 0.00003. If you divided 0.00003 by 10 you would get 0.0003.
Hopefully, this was useful.
Answer:
76.16 kilograms of food
Step-by-step explanation:
Number of cyclist = 32
Food per cyclist = 8.33 kilograms
Days of the trip = 7 days
Food per cyclist per day = 8.33 kg / 7
= 1.19kg food per day for each cyclist
how many kilograms of food will the group be carrying at the end of Day 5?
5 days out of 7 days = 2 days
Each cyclist will have to carry = 2 × 1.19 kg of food for the remaining two days
= 2 × 1.19
= 2.38 kilograms of food for two days
32 cyclist for 2 days = 32 × 2.38 kg of food
= 76.16 kilograms of food
The group will be carrying 76.16 kilograms of food at the end of Day 5
Answer:
pretty sure it's 56 I could be wrong though
Answer: the graph crosses the x-axis at x = -3
<u>Step-by-step explanation:</u>
y = (x + 3)³
To find where the graph crosses the x-axis, let y = 0 and solve for x:
0 = (x + 3)³
0 = (x + 3) with a multiplicity of 3
-3 = x with a multiplicity of 3.
Since multiplicity is an ODD number, the graph CROSSES the x-axis at x = -3
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<u>Graph:</u>
- Leading coefficient is POSITIVE so right side goes to +∞
- Degree of polynomial is ODD so left side goes to -∞
<em>graph is attached</em>
