Answer:
a) The genotype of her father = "aa".
The genotype of her mother = "Aa".
The genotype of Sally is "Aa".
b) 1/2
c) 1/2
Explanation:
a) Sally's father has alkaptonuria. So, the genotype of her father is "aa". Her mother is normal. Since her brother is affected by the disease, he should be homozygous recessive (aa). This means that the mother also has one copy of "a" allele and is heterozygous dominant (Aa). A cross between Aa (mother) and aa (father) would give 50% affected progeny with "Aa" genotype. So, the genotype of Sally is "Aa".
b) The genotype of her mother= Aa
The genotype of her father = aa
Aa x aa = 1/2 Aa (affected): 1/2 aa (normal)
So, if Sally's parents have another child, there is a 1/2 probability that this child will have alkaptonuria.
c) The genotype of Sally = Aa
Genotype of the man Sally marries= aa (since he is affected with alkaptonuria)
Aa x aa= 1/2 Aa (affected): 1/2 aa (normal)
There is a 1/2 probability that their child will have alkaptonuria.
Sorry I am late on answering the question, if u don’t know what it is still, the answer I believe is D!
Answer:
mitochondria
Explanation:
Both bacteria and mitochondria have their own cell
Answer: D. The genotype would be Gg and then phenotype would be yellow
Explanation:
