Answer:
C because its the only one that fits the question its asking. 12-6 8-4 4-2
Step-by-step explanation:
I'm sorry i don't know what the question is asking for but this is what i get:
for the food to be within the budget:
6x + 4y<span> ≤ 100
6(12) + 4( 5.5) </span><span> ≤ 100
72 + 22 </span><span> ≤ 100
94 </span><span> ≤ 100
with this, they could buy 6 pizzas and 4 sodas, as well as an extra soda
so that's 6 pizzas and 5 sodas to stay under budget.
sorry if i'm wrong</span>
They can be chosen in 12,444 ways.
There are three different scenarios that have more boys being chosen than girls:
5 boys and 0 girls
4 boys and 1 girl
3 boys and 2 girls
We will set up combinations for all 3 of these scenarios:
![(_{18}C_5\times{_{19}C_0)+(_{18}C_4\times_{19}C_1)+(_{18}C_3\times_{19}C_2)](https://tex.z-dn.net/?f=%28_%7B18%7DC_5%5Ctimes%7B_%7B19%7DC_0%29%2B%28_%7B18%7DC_4%5Ctimes_%7B19%7DC_1%29%2B%28_%7B18%7DC_3%5Ctimes_%7B19%7DC_2%29)
44, 55, 1010 and 4040
I knew I was smart :)