Answer:
CI = (98.11 , 98.49)
The value of 98.6°F suggests that this is significantly higher
Step-by-step explanation:
Data provided in the question:
sample size, n = 103
Mean temperature, μ = 98.3
°
Standard deviation, σ = 0.73
Degrees of freedom, df = n - 1 = 102
Now,
For Confidence level of 99%, and df = 102, the t-value = 2.62 [from the standard t table]
Therefore,
CI = 
Thus,
Lower limit of CI = 
or
Lower limit of CI = 
or
Lower limit of CI = 98.11
and,
Upper limit of CI = 
or
Upper limit of CI = 
or
Upper limit of CI = 98.49
Hence,
CI = (98.11 , 98.49)
The value of 98.6°F suggests that this is significantly higher and the mean temperature could very possibly be 98.6°F
Answer:
y= -1/9(x-1)^2 +2
Step-by-step explanation:
The vertex is at (1,2) and another point is at (-2,1).
We know the vertex form of a parabola is
y= a(x-h)^2 +k where (h,k) is the vertex
Substituting the vertex in
y= a(x-1)^2 +2
We have another point, (-2,1)
Substitue this in with x=-2 and y =1. This will let us find a
1 = a(-2-1)^2 +2
1 = a (-3)^2 +2
1 = a*9 +2
Subtract 2 from each side
1-2 = 9a +2-2
-1 = 9a
Divide by 9
-1/9 = 9a/9
-1/9 =a
Putting this back into the equation
y= -1/9(x-1)^2 +2
<span>
Over the y-axis
</span>
<span>(x, y) → (−x, y) so ( -5, -3)</span>
Answer:
7.
(x + 1)² = x² + 2x + 1
as the original function, but the turnaround is now (still at x = 0) at y = 1 instead of y = 0.
and the graph is "narrower". for x = 1 and x = -1, y = 4. for x = 2 and x = -2, y = 9
8.
= x² - 2
it is exactly the same graph, just 2 units down in y direction (the turnaround is at x = 0. y = -2).
9.
the right answer is D
Step-by-step explanation:
9.
the y values of +x values now become the same values for the -x values. and vice versa.
