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Akimi4 [234]
3 years ago
9

I got it wiring but I don’t know what I did wrong

Mathematics
1 answer:
vichka [17]3 years ago
7 0

Answer:

because the answer is 6.601 not 6.501

Step-by-step explanation:

you must have done the work wrong

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Use the remainder Theorem and synthetic division to find p(3) for p(x) = x4 + x3 -x2 - 2x
maxonik [38]

You do not need to use the remainder theorem to find p(3). Just plugin 3 where the x is located in

x^4 + x^3 - x^2 - 2x

3^4 + 3^3 - 3^2 - 2(3) = 93

Answer is a.

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3 years ago
Suppose you multiply a whole number greater than 1 by the fraction 3/5. Will the product be greater than, less than, or equal to
Virty [35]
Greater than. For example if you multiply 2 by 3/5 the answer is 1 1/5 which is greater than 3/5
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2 years ago
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In a right triangle one leg measures a quarter of the other, how much do its acute angles measure? with procedure please​
KATRIN_1 [288]

Answer:

The answer to your question is 14° and 76°

Step-by-step explanation:

Data

leg 1 = x

leg 2 = x/4

angle 1 = ?

angle 2 = ?

Process

To solve problem use trigonometric functions. We must use the trigonometric function that relates both legs (tangent).

    tangent Ф = Opposite side / Adjacent side

-Substitution

    tan Ф = (x/4) / x

-Simplification

    tan Ф = x / 4x

    tan Ф = 1/4

-  Find Ф

     Ф = tan⁻¹(1/4) =  14°

- Find the other acute angle

  The sum of the internal angles in a triangles equals 180°

       Ф + Ф₁ + 90° = 180

-Solve for Ф₁

        Ф₁  = 180 - 90 - 14

-Result

        Ф₁ = 76°              

3 0
2 years ago
Choose the point-slope form of the equation below that represents through the points (-3,2) and (2,1)
s2008m [1.1K]

Answer:

-1/4

Step-by-step explanation:

2-1 over -3-1 = 1/-4

3 0
3 years ago
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mojhsa [17]

Answer:

The 4th option.

Step-by-step explanation:

Rational numbers are numbers which can be expressed as a fraction. Irrational numbers are numbers which can't be expressed as a fraction. Square root 16 is a perfect square so it is a rational number.

4 0
2 years ago
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