Answer:
The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Step-by-step explanation:
Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.
But,
<P = 048°
<Q = -
= 0
Sum of angles in a triangle =
<P + <Q + <S =
048° + 0 + <S =
+ <S =
<S = -
=
<S =
Applying the Sine rule,
= =
=
=
=
⇒ y =
= 12.703
y = 12.70 km
=
=
=
⇒ x =
= 10.0475
x = 10.05 km
Thus,
the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Y = -2x + 6
I think this is it
6.6. 2.2*3= 6.6
i hope this makes since
The awnser has to be 26??