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Bad White [126]
3 years ago
14

Does the rule y=6x^7 represent an exponential function

Mathematics
2 answers:
LiRa [457]3 years ago
5 0
Yes it does thats  what the carrot is for
weeeeeb [17]3 years ago
3 0

An exponential function is a function in which the variable is in the exponent.

Functions of the type : y=x^{2}

Here the exponent is an integer.

Such functions are called Arithmetic functions.

Functions of the type

y = 2 ^x

Here the exponent of 2 is a variable.

Such functions are called exponential functions

We are given y =6 x^7.

Here the variable is base & the exponent is an integer.

So does not represent an exponential function.

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Here is a list of numbers.
DanielleElmas [232]
60! 20 times 3 is 60
7 0
3 years ago
Given that,
Mrac [35]

Answer:

0.6990

Step-by-step explanation:

We have:

$log_{10} (10)=1$

$\therefore \log_{10}(2\times 5)=1$

$\implies \log_{10}(2)+ \log_{10}(5)=1$

$\implies \log_{10}(5)=1-\log_{10}(2)$

$\implies \log_{10}(5)=1-0.3010=\boxed{0.6990}$

3 0
4 years ago
Which retirement plan does not potentially involve contributions from an individual’s employer? A. Traditional IRA B. Social Sec
Talja [164]

Answer:

IRA

Step-by-step explanation:

I looked it up

6 0
4 years ago
Use the double-angle formula for cosine to establish the identity cos (theta / 2) = ±cos(theta) + 1 / 2 .
Nimfa-mama [501]

Answer:

See explanation and proof below.

Step-by-step explanation:

For this case we want to proof this identity:

cos(\frac{\theta}{2}) = \pm \sqrt{\frac{1+ cos(x)}{2}}

And we need to us the double angle formula given by:

cos^2 (x) = \frac{1+ cos (2x)}{2}

If we use a substitution for example x = \frac{\theta}{2} we see that the double angle formila is given by:

cos^2(\frac{\theta}{2}) = \frac{1+ cos (2\frac{\theta}{2})}{2}

And we got:

cos^2(\frac{\theta}{2}) = \frac{1+ cos (\theta)}{2}

And if we apply sqaure root on both sides we got:

cos(\frac{\theta}{2}) = \pm \sqrt{\frac{1+ cos (\theta)}{2}}

And that complete the proof

4 0
4 years ago
Does arctan(5n) converge or diverge?
Travka [436]
If you mean, "does the sequence a_n=\arctan(5n) converge", then yes, since \lim\limits_{n\to\infty}\arctan n=\dfrac\pi2.

If you mean, "does the series \sum\limits_n\arctan(5n) converge", then no, for the reason above (the summand passes the nth limit test for divergence, so the series diverges).
3 0
4 years ago
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