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Bad White [126]
3 years ago
14

Does the rule y=6x^7 represent an exponential function

Mathematics
2 answers:
LiRa [457]3 years ago
5 0
Yes it does thats  what the carrot is for
weeeeeb [17]3 years ago
3 0

An exponential function is a function in which the variable is in the exponent.

Functions of the type : y=x^{2}

Here the exponent is an integer.

Such functions are called Arithmetic functions.

Functions of the type

y = 2 ^x

Here the exponent of 2 is a variable.

Such functions are called exponential functions

We are given y =6 x^7.

Here the variable is base & the exponent is an integer.

So does not represent an exponential function.

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Schach [20]

Answer:

три три быдет три незнаю точно

7 0
3 years ago
Read 2 more answers
Jasmine works at the public library after school. She makes $7.00 per hour. She cannot work more than 15 hours per
sveta [45]

Answer:

the answer is mx +B plus the quradratic formula

3 0
3 years ago
Help me with the math pretty easy
erik [133]
100 and other one would be 80
5 0
3 years ago
Triangle TUV is transformed according to the rule . What are the coordinates for U’?
Ira Lisetskai [31]
X is -6 and y is 4 that the coordinates for u 
8 0
4 years ago
Please show step by step of working out the value of r for which is A is aminimum and calculate the minimum surface area of the
almond37 [142]

Answer:

The minimum surface area of the container is 276.791 square units.

Step-by-step explanation:

Let be A(r) = \pi\cdot r^{2} + \frac{1000}{r}, \forall \,r \in \mathbb{R}, r \geq 0. The first and second derivatives of such function are, respectively:

First derivative

A'(r) = 2\cdot \pi \cdot r -\frac{1000}{r^{2}}

Second derivative

A''(r) = 2\cdot \pi +\frac{2000}{r^{3}}

The critical values of r are determined by equalizing first derivative to zero and solving it: (First Derivative Test)

2\cdot \pi \cdot r -\frac{1000}{r^{2}} = 0

2\cdot \pi \cdot  r^{3} - 1000 = 0

r = \sqrt[3]{\frac{1000}{2\pi} }

r \approx 5.419 (since radius is a positive variable)

To determine if critical value leads to an absolute minimum, this input must be checked in the second derivative expression: (r \approx 5.419)

A''(5.419) = 2 + \frac{2000}{5.419^{3}}

A''(5.419) = 14.568

The critical value leads to an absolute minimum, since value of the second derivative is positive.

Finally, the minimum surface area of the container is:

A(5.419) = \pi\cdot (5.419)^{2} + \frac{1000}{5.419}

A(5.419) \approx 276.791

The minimum surface area of the container is 276.791 square units.

7 0
3 years ago
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