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ra1l [238]
3 years ago
13

An acute triangle has two sides measuring 8 cm and 10cm. What is the best possible range of values for the third side, s?

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0

Answer:

The range of the possible values for the third side s is the interval  (6,12.8)

6\ cm < s < 12.8\ cm

see the explanation

Step-by-step explanation:

we know that

The <u><em>Triangle Inequality Theorem</em></u> states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

Let

s ----> the length of the third side of the triangle

Applying the Triangle Inequality Theorem

1)

8+10 > s

18 > s

s< 18\ cm

2)

s+8>10

s > 10-8

s > 2\ cm

therefore

The range of the possible values for the third side s, applying the triangle inequality theorem is the interval (2,18)

2\ cm < s < 18\ cm

All real number greater than 2 centimeters and less than 18 centimeters

Remember that

Applying the Pythagorean theorem

In an acute triangle

c^2

First case

c=10 cm,a=8 cm, b=s

10^2

Second case

a=8 cm,b=10 cm, c=s

s^2

The range of the possible values for the third side s, applying the Pythagorean Theorem is the interval (6,12.8)

therefore

The range of the possible values for the third side s, is the interval (6,12.8)

6\ cm < s < 12.8\ cm

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