If b=a, where one the number line will b appear

1500 soldiers arrive at a training camp. A few soldiers desert the camp. The drill sergeants divide the remaining soldiers into

iren [92.7K]

Answer:

The number of deserters is 34.

Step-by-step explanation:

We have to calculate the number of desertors in a group of 1500 soldiers.

The sergeant divides in groups of different numbers and count the lefts over.

If he divide in groups of 5, he has on left over. The amount of soldiers grouped has to end in 5 or 0, so the total amount of soldiers has to end in 1 or 6.

If he divide in groups of 7, there are three left over. If we take 3, the number of soldiers gruoped in 7 has to end in 8 or 3. The only numbers bigger than 1400 that end in 8 or 3 and have 7 as common divider are 1428 and 1463.

If we add the 3 soldiers left over, we have 1431 and 1466 as the only possible amount of soldiers applying to the two conditions stated until now.

If he divide in groups of 11, there are three left over. We can test with the 2 numbers we stay:

$(1431-3)/11=1428/11=129.82\\\\(1466-3)/11=1463/11=133$

As only 1466 gives a possible result (no decimals), this is the amount of soldiers left.

The deserters are 34:

$D=1500-1466=34$

6 0

3 years ago

Kim paid 3/7 of a bill, Sherri paid 35% of the bill, and Judy paid the rest.

-Dominant- [34]

A:Kim paid the most
Since 3/7 is 42.8%

5 0

3 years ago

Read 2 more answers

The normal monthly temperatures (°F) for Omaha, Nebraska, are recorded below.

AfilCa [17]

Answer

$y = 28 \sin(\frac{\pi}{6} - \frac{2\pi}{3}) + 49$

Step by Step Explanation

Given

See attachment for table

Required

Determine the sinusoidal function

The sinusoidal function is represented as:

$y = A \sin(Bx + C) + D$

Where

$|A| = Amplitude$

And it is calculated as:

$A = \frac{1}{2}[Highest - Least]$

From the table:

Highest = 77 and Least = 21

So:

$A = \frac{1}{2}[77 - 21]$

$A = \frac{1}{2}[56]$

$A = 28$

B is calculated as:

$Period = \frac{2\pi}{B}$

The period is 12 i.e. 12 months

So:

$\frac{2\pi}{B} = 12$

$B = \frac{2\pi}{12}$

$B = \frac{\pi}{6}$

C is calculated as:

$\frac{C}{B} = -4$

$C = -4 * B$

$C = -4 * \frac{\pi}{6}$

$C = -2 * \frac{\pi}{3}$

$C = -\frac{2\pi}{3}$

Lastly, D is calculated as:

$D = Least + A$

So:

$D =21 + 28$

$D=49$

So, the function is:

$y = A \sin(Bx + C) + D$

$y = 28 \sin(\frac{\pi}{6} - \frac{2\pi}{3}) + 49$

8 0

3 years ago

Cassie bought a pair of loafers for $29.95. Tights were on sale for 3 pairs for $10.00. She gave the clerk $60.00. How much chan

monitta

Answer:

$20.05 is Cassie's change

Step-by-step explanation:

60.00-29.95=30.05

30.05-10=20.05

5 0

4 years ago

10. Determine the open interval(s) on which the function f(x) = 12x - x^3 is increasing.

Gre4nikov [31]

Answer:

$\large\boxed{x\in(-2,\ 2)}$

Step-by-step explanation:

$f(x)=12x-x^3$

Calculate the derivative of the function:

$f'(x)=\left(12x-x^3\right)'=(12x)'-\left(x^3\right)'=12-3x^2$

Calculate the zeros of the derivative:

$f'(x)=0\Rightarrow12-3x^2=0\qquad\text{add}\ 3x^2\ \text{to both sides}\\\\3x^2=12\qquad\text{divide both sides by 3}\\\\x^2=4\to x=\pm\sqrt4\\\\x=\pm2$

Let's check the derivative sign:

$f'(x)>0\iff12-3x^2>0\qquad\text{use the distributive property}\\\\-3(x^2-4)>0\\\\-3(x^2-2^2)>0\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\-3(x-2)(x+2)>0\\^{\qquad x=2\qquad x=-2$

Sketch a parabola open down

(before the brackets there is the number -3 < 0)

Look at the picture.

Where the derivative is negative, the function decreases.

Where the derivative is positive, the function increases.

Therefore your answer is:

$x\in(-2,\ 2)$

3 0

4 years ago