Find the line parallel to y = -3x + 1 that passes through (9, 0). Plls Hurry I'm being timed
1 answer:
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Inequalities are used to show the relationship between unequal expressions
- <em>The set notation of (5) and (6) are: </em>
<em> and </em>
<em>.</em>
- <em>See attachmen</em>t for the graphs
The following should be notated when plotting the graph of an inequality
- < and > are represented with open circles, while
and
are represented with closed circles
- The arrows of
and
point to the left, while the arrows of
and
So, we have:
Rewrite as:
The graph of will point to the right, and it will use an open circle
Split the inequality:
and
<em>It is not possible for -6 to be less than x and at the same time, x is greater than or equal to -2.</em>
<em />
Hence. cannot be represented on a graph
Split the inequality:
and
means that -4 is less than x or x is greater than -4.
So, we have:
and
If and
, then we make use of
because it contains more values of x.
The graph of will point to the right, and it will use an open circle
Read more about inequalities at:
All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is
Multiply both sides by <em>r</em> :
Subtract the latter sum from the first, which eliminates all but the first and last terms:
Solve for :
Then as gets arbitrarily large, the term will converge to 0, leaving us with
So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18