I guess you mean:
X^2 - X - 6 and X^2 - 5X + 6
X^2 - X - 6 = (X + 2)(X − 3)
X^2 - 5X + 6 = (X − 2)(X − 3)
Based on that, their common factor is:
(X - 3)
3x + 4y = 5
<u>-5x - 4y = -11</u>
-2x = -6
-<u>2x</u> = <u>-6</u>
-2 -2
x = 3
3(3) + 4y = 5
9 + 4y = 5
<u> -9 -9</u>
4y = -4
<u>4y</u> = <u>-4</u>
4 4
y = -1
(x, y) = (3, -1)
Answer:
x=-2
do your box method and find what multiplies to C and adds to B
to check your answer substitute x with what x=
<span>There are two approaches to translate this inquiry, to be specific:
You need to know a number which can go about as the ideal square root and also the ideal block root.
You need to know a number which is an ideal square and in addition an ideal 3D shape of a whole number.
In the primary case, the arrangement is straightforward. Any non-negative whole number is an ideal square root and in addition a flawless solid shape foundation of a bigger number.
A non-negative whole number, say 0, is the ideal square foundation of 0 and additionally an immaculate shape base of 0. This remains constant for all non-negative numbers starting from 0 i.e. 0, 1, 2, 3, 4, 5, 6, 7, 8, 9
In the second case as well, the arrangement is straightforward however it involves a more legitimate approach than the primary choice.
A flawless square is a number which contains prime variables having powers which are a different of 2. So also, a flawless block is a number which includes prime variables having powers which are a numerous of 3.
Any number which includes prime components having powers which are a various of 6 will be the answer for your inquiry; a case of which would be 64 which is the ideal square of 8 and an ideal 3D shape of 4. For this situation, the number 64 can be spoken to as prime variables (i.e. 2^6) having powers (i.e. 6) which are a different of 6.</span>
Answer:
x= 14.0 (nearest tenth)
Step-by-step explanation:
Please see the attached picture for the full solution.