To find the mean, u add up all the numbers and divide by how many numbers there are.
the mean : (4 + 8 + 5 + 7 + 6) / 5 = 30/5 = 6
for the median (the middle number)...first, put ur numbers in order...doing this is very important
4,5,(6),7,8.....the median (middle number) = 6
so both ur mean and ur median are 6 <==
Answer:
the first one
Step-by-step explanation:
![2(\sqrt[3]{16x^{3}y })+4(\sqrt[3]{54x^{6}y^{5} } )= 2(2x\sqrt[3]{2y })+4(3x^{2} y\sqrt[3]{2y^{2} } ) = 4x(\sqrt[3]{2y })+12x^{2} y(\sqrt[3]{2y^{2} } )](https://tex.z-dn.net/?f=2%28%5Csqrt%5B3%5D%7B16x%5E%7B3%7Dy%20%7D%29%2B4%28%5Csqrt%5B3%5D%7B54x%5E%7B6%7Dy%5E%7B5%7D%20%20%7D%20%29%3D%202%282x%5Csqrt%5B3%5D%7B2y%20%7D%29%2B4%283x%5E%7B2%7D%20y%5Csqrt%5B3%5D%7B2y%5E%7B2%7D%20%7D%20%29%20%3D%204x%28%5Csqrt%5B3%5D%7B2y%20%7D%29%2B12x%5E%7B2%7D%20y%28%5Csqrt%5B3%5D%7B2y%5E%7B2%7D%20%7D%20%29)
It's January, they have till July => 6 months including January
half of $8000 is $4000 in 6 months
4000/6 = $666.66 per month
Johnny should save that much money each month
7y^3(3y^2-2)-(3y^2-2)
(3y^2-2)(7y^3-1)
