Team B has a mode of 60, which is the highest mode of all three teams. Team A has a mode of 48 and Team C has a mode of 30. Mode is the number that occurs most frequently in the set of data.
Distance = 100 m = 100/1000 = 0.1 km speed of train = 50 km/hr speed of horse = 56 km/hr resultant speed = (56 – 50) 6 km/hr time = distance/speed time = 0.1/6 = 1/60 hr = 1 min
Answer:
B. 6x2+x+7
Step-by-step explanation:
combine like terms
3x^2+3x^2= <u>6x^2</u>
<u>x</u>
3+4=<u>7</u>
13=1+4s
So you find S
So you take out 1, and subtract 1 from thirteen
12=4s so then you divide it by 4
12÷4=3
s=3
It would have the be B. 16
