Answer:
7 seconds
Step-by-step explanation:
Hello There!
I had created a graph to make it easier to understand
So when y = 0 is when the ball is at the ground
when y = 0 x = 7 so it took about 7 seconds for the ball to hit the ground
Sqrt(1-3x)=x+3
[sqrt(1-3x)]^2=(x+3)^2
1-3x=(x+3)(x+3)
1-3x=x^2+6x+9
-3x=x^2+6x+8
0=x^2+9x+8
The answers are -1 and -8 BUT, we have to plug them back into the original equation to make sure we don't get a negative under the square root sign.
After doing this, we realize that only -1 works, so the answer is x=-1
Sorry that this took forever to answer. I was thinking of a good way to explain this, and if you need any further explanation, message me:)
Best wishes:)
For this case we must find the product of the following expression:
![\sqrt [3] {5} * \sqrt {2}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B5%7D%20%2A%20%5Csqrt%20%7B2%7D)
By definition of properties of powers and roots we have:
![\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%20%5E%20m%7D%20%3D%20a%20%5E%20%7B%5Cfrac%20%7Bm%7D%20%7Bn%7D%7D)
We rewrite the expression using the lowest common index of 6, then:

We rewrite the terms in an equivalent way:

We rewrite the expression using the property mentioned:
![\sqrt [6] {5 ^ 2} * \sqrt [6] {2 ^ 3} =](https://tex.z-dn.net/?f=%5Csqrt%20%5B6%5D%20%7B5%20%5E%202%7D%20%2A%20%5Csqrt%20%5B6%5D%20%7B2%20%5E%203%7D%20%3D)
We combine using the product rule for radicals:
![\sqrt [n] {a} * \sqrt [n] {b} = \sqrt [n] {ab}](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%7D%20%2A%20%5Csqrt%20%5Bn%5D%20%7Bb%7D%20%3D%20%5Csqrt%20%5Bn%5D%20%7Bab%7D)
So:
![\sqrt [6] {5 ^ 2 * 2 ^ 3} =\\\sqrt [6] {25 * 8} =\\\sqrt[6]{200}](https://tex.z-dn.net/?f=%5Csqrt%20%5B6%5D%20%7B5%20%5E%202%20%2A%202%20%5E%203%7D%20%3D%5C%5C%5Csqrt%20%5B6%5D%20%7B25%20%2A%208%7D%20%3D%5C%5C%5Csqrt%5B6%5D%7B200%7D)
ANswer:
Option b
You set 49 equal to 8x - 15
So
8x - 15 = 49
+15 + 15
8x = 64
Then divide by 8
X= 8
Answer:
a = -4.
Step-by-step explanation:
25(√5)^a * (√5) ^3 = 5√5
25*5^a/2 * 5^3/2 = 5*5^1/2
25*5^a/2 = 5*5^1/2 / 5^3/2
25*5^a/2 = 5^1 *5^1/2 / 5^3/2
25*5^a/2 = 5^3/2 / 5^3/2 = 1
5^a/2 = 1/25 = 5^-2
The bases are equal, so
a/2 = -2
a = -4.