All categories

2 years ago

Can someone please help me on this question

Mathematics

1 answer:

klemol [59]2 years ago

6 0

C = 31.4 (10pi)

The radius is half of the diameter
To find the circumference multiply the diameter by pi (3.14 )
The radius is 5 so the diameter is 10
3.14•10=31.4

You might be interested in

The graph shows the relationship between mass and volume for pure silver. Use the graph to determine the density of pure silver

Natalija [7]

Answer:

C. Slope and $10.49 g/cm^3$

Step-by-step explanation:

We're missing the graph itself, but I can make an educated guess:

- Assuming x = volume and y = mass:

$p = \frac{m}{v}$

density = mass/volume

x = volume = run

y = mass = rise

mass/volume = rise/run = slope

The slope of the line (assuming the graph is purely linear) represents mass/volume, which is the formula for density.

I had to Google the density of silver itself. Do the math from the graph for a more appropriate answer, as the graph may be less scientifically precise.

7 0

3 years ago

Someone please help me on this!

Alexxx [7]

Answer & Step-by-step explanation:

This can be proven with the SAS theorem (side-angle-side)

With a perpendicular bisector, the line it bisects is cut directly in half. This creates two equal sides:

$GJ=IJ$

and it creates two 90° angles:

∠ $GJH=$ ∠ $IJH$

And because of the reflexive property of congruence:

$JH=JH$

Side-Angle-Side.

:Done

6 0

3 years ago

A study indicates that 37% of students have laptops. You randomly sample 30 students. Find the mean and the standard deviation o

Brilliant_brown [7]

Answer:

The mean and the standard deviation of the number of students with laptops are 1.11 and 0.836 respectively.

Step-by-step explanation:

Let X = number of students who have laptops.

The probability of a student having a laptop is, P (X) = p = 0.37.

A random sample of n = 30 students is selected.

The event of a student having a laptop is independent of the other students.

The random variable X follows a Binomial distribution with parameters n and p.

The mean and standard deviation of a binomial random variable X are:

$\mu=np\\\sigma=\sqrt{np(1-p)}$

Compute the mean of the random variable X as follows:

$\mu=np=30\times0.37=1.11$

The mean of the random variable X is 1.11.

Compute the standard deviation of the random variable X as follows:

$\sigma=\sqrt{np(1-p)}=\sqrt{30\times0.37\times(1-0.37)}=\sqrt{0.6993}=0.836$

The standard deviation of the random variable X is 0.836.

5 0

3 years ago

sana is senior to Mona by 18 years after 6 years.Sana will be twice as old as Mona. find Mona,s percentage

Gwar [14]

Let
Present age of Sana = s
Present age of Mona = m

Sana is senior to Mona by 18 years
s=m+18............(1)

After 6 years
Sana will be = s+6
Mona will be = m+6
Then
Sana will be twice as old as Mona
(s+6)=2(m+6)
s+6=2m+12
s=2m+12-6
s=2m+6.............(2)
Put the value of s from (2) to (1)
2m+6=m+18
2m-m=18-6
m=12
Put the value of m in (1)
s=m+18
s=12+18
s=30

Present age of Sana = s = 30 years old
Present age of Mona = m = 12 years old

3 0

2 years ago

Two dice are rolled, and the sum of the face values is six. What is the probability that at least one of the dice came up a thre

gizmo_the_mogwai [7]

Answer : $P(\text{ atleast one of the dice come up 3})= \frac{1}{5}$