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Zepler [3.9K]
3 years ago
14

Find the slope of the line (-9, 1) (1, 9)​

Mathematics
2 answers:
dezoksy [38]3 years ago
6 0

Answer:

Slope=4/5

Step-by-step explanation:

This is the formula to find the slope of lines:

y2-y1/x2-x1 (look it up to learn more)

9-1/1+9

8/10

4/5

The slope is 4/5

Hope this helps :)

enot [183]3 years ago
3 0
It is 4/5 you have to add the 9 to the1 and add the 1 to the -9
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Please help me with this question URGENT PLEASE ANSWER THIS MATH QUESTION
lesya [120]

Answer:

(4,0)

Step-by-step explanation:

The object is first at (0,0)

It is reflected across line x=-2, this means you draw the mirror line at x=-2 and count 2 equal units backwards to get the image.The image will be at ;y=0\\\\x=-2-2=-4\\\\\\=(-4,0)

The image (-4,0) is then reflected on the y-axis

You know reflection on the y-axis, the y-coordinate remains the same but the x-coordinate is changed to its opposite sign.

Hence;

(- -4,0)= (4,0)

The image will move 8 units towards positive x-axis.This is the same as moving 4 units from the mirror line at (0,0) and land at (4,0)

6 0
3 years ago
You’ve observed the following returns on Crash-n-Burn Computer’s stock over the past five years: 14 percent, –9 percent, 16 perc
MatroZZZ [7]

Answer:

a. 9%

b. 0.01445

c. 12.02%

Step-by-step explanation:

n = 5 years

Return rates = 14%, –9%, 16%, 21%, and 3%

a. Arithmetic average return

A= \frac{14-9+16+21+3}{5} \\A=9.00

b. Historical variance (to 5 decimal places)

V= \frac{\sum (X_i-A)^2}{n-1} \\V= \frac{(0.14-0.09)^2+(-0.09-0.09)^2+(0.16-0.09)^2(0.21-0.09)^2(0.03-0.09)^2}{5-1}\\ V=0.01445

c. Standard deviation.

s = \sqrt{V} \\s= \sqrt{0.01445}\\s=0.1202 = 12.02\%

8 0
3 years ago
Please help me with this question
san4es73 [151]

Step-by-step explanation:

Given: f'(x) = x^2e^{2x^3} and f(0) = 0

We can solve for f(x) by writing

\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx

Let u = 2x^3

\:\:\:\:du=6x^2dx

Then

\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du

\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k

We know that f(0) = 0 so we can find the value for k:

f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}

Therefore,

\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)

5 0
2 years ago
A sports writer wished to see if a football filled with helium travels farther, on average, than a football filled with air. To
Vesnalui [34]

Answer:

(-3.07, 11.07)

Step-by-step explanation:

Given that a sports writer wished to see if a football filled with helium travels farther, on average, than a football filled with air. To test this, the writer used eighteen adult male volunteers. These volunteers were randomly divided into two groups of nine subjects each.

Group   Group One     Group Two  

Mean 300.00 296.00

SD 8.00 6.00

SEM 2.67 2.00

N 9     9    

The mean of Group One minus Group Two equals 4.00

 

standard error of difference = 3.333

   df = 16

t = 1.2000

Margin of error = 3.3333* t critical = 3.3333*2.121

 95% confidence interval of this difference: From -3.07 to 11.07

7 0
2 years ago
Area of the base=
umka21 [38]

Answer:

16 pi

Step-by-step explanation:

The base is the circle

A = pi r^2

A = pi (4)^2

A = 16 pi

3 0
2 years ago
Read 2 more answers
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