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3 years ago

Help memememememe please

Mathematics

2 answers:

lawyer [7]3 years ago

5 0

Answer:

∠b = 54°

they add up to 180

7x + 14 + 5x - 26 = 180

12x = 192

x=16

thus ∠b = 54°

Step-by-step explanation:

Leviafan [203]3 years ago

4 0

Answer:

good evening good evening good evening good evening

Step-by-step explanation:

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Three friends paid 26.25 to see a movie how much did each ticket cost

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$8.75 is the answer.
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klemol [59]

Your question is calling the figure ABCD, but the image is showing PQRS

Using the letters that you wrote:

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In parallelogram ABCD, AD = 12 in, m∠C = 46º, m∠DBA = 72º. Find the area of ABCD

dmitriy555 [2]

Answer:

The area of parallelogram ABCD is $78.42 \mathrm{in}^{2}$

Explanation:

Given:

AD = 12 in

$m \angle C=46^{\circ}$

$m \angle D B A=72^{\circ}$

To Find:

The area of parallelogram ABCD=?

Solution:

When we construct the parallelogram with the given data, we get a parallelogram formed by 12 cm as one side and an angle with 46 degrees.

The area of the parallelogram can be calculated by $a b * \sin (a n g l e)$

Substituting the value of a=12 we have

$\text { Area of parallelogram }=12 * \text { bsin } 46$

<u>To find the value of b, </u>

We know that area of a triangle can be expressed as,

$\text { Area of triangle }=(A b / 2) \sin (\text {angle})$

So,

$(12 * B D / 2) * \sin 46=(A B * B D / 2) * \sin 72$

Cancelling BD and 2 on both sides we get,

$12 * \sin 46=A B * \sin 72$

$A B=12 * \frac{\sin 46}{\sin 72}$

Therefore,

$b=\frac{12 \sin 46}{\sin 72}$

Substituting the value of b,

$=12 *\left(\frac{12 \sin 46}{\sin 72}\right) * \sin 46$

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