An arithmetic sequence has second term 28 and the fifth term 52. (3 marks) a. Find u1 and d. b. Find u10
1 answer:
Answer: See explanation
Step-by-step explanation:
Second term = a + d = 28 ....... i
Fifth term = a + 4d = 52 ......... ii
Subtract equation I from ii
3d = 24
d = 24/3 = 8
d = common difference = 8
Since a + d = 28
a + 8 = 28
a = 28 - 8 = 20
First term = a = 20
u10 = a + (n-1)d
= a + (10-1)8
= 20 + (9 × 8)
= 20 + 72
= 92
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