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3 years ago

How do you round to the greatest place value

2 answers:

6 0

Example: round 24,356 the greatest place value.
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> Rounding Numbersto the Greatest Place Value < you are here
Example-2: round 8,636 to the greatest place value.

Look to the right of the number in the thousands
place. It's a 6, so round up.

8,636 is rounded to 9,000 because the highest place
value of that number is in the thousands place.

Bess [88]3 years ago

3 0

Pretend if you had 8,999 you would round up to you would do 9,000

You might be interested in

There are 9,481 eligible voters in a precinct. 500 were selected at random and asked to indicate whether they planned to vote fo

maria [59]

Answer:

The confidence limits for the proportion that plan to vote for the Democratic incumbent are 0.725 and 0.775.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Of the 500 surveyed, 350 said they were going to vote for the Democratic incumbent.

This means that $n = 500, \pi = \frac{350}{500} = 0.75$

80% confidence level

So $\alpha = 0.2$ , z is the value of Z that has a pvalue of $1 - \frac{0.2}{2} = 0.9$ , so $Z = 1.28$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 - 1.28\sqrt{\frac{0.75*0.25}{500}} = 0.725$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 + 1.28\sqrt{\frac{0.75*0.25}{500}} = 0.775$

The confidence limits for the proportion that plan to vote for the Democratic incumbent are 0.725 and 0.775.

8 0

3 years ago

The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it

brilliants [131]

Answer:

(a) 11.25 and 1.68

(b) 0.1651

(c) 0.3903

(d) 0.6865

Step-by-step explanation:

We are given that GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 75% of the cases and suppose the 15 cases reported today are representative of all complaints.

This situation can be represented through Binomial distribution as;

$P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....$

where, n = number of trials (samples) taken = 15

r = number of success

p = probability of success which in our question is % of cases in

which customer problems are resolved on the same day, i.e.;75%

So, here X ~ $Binom(n=15,p=0.75)$

(a) Expected number of problems to be resolved today = E(X)

E(X) = $\mu$ = n * p = 15 * 0.75 = 11.25

Standard deviation = $\sigma$ = $\sqrt{n*p*(1-p)}$ = $\sqrt{15*0.75*(1-0.75)}$ = 1.68

(b) Probability that 10 of the problems can be resolved today = P(X = 10)

P(X = 10) = $\binom{15}{10}0.75^{10}(1-0.75)^{15-10}$

= $3003*0.75^{10} *0.25^{5}$ = 0.1651

= $\binom{15}{10}0.75^{10}(1-0.75)^{15-10}+\binom{15}{11}0.75^{11}(1-0.75)^{15-11}$

= $3003*0.75^{10} *0.25^{5} + 1365*0.75^{11} *0.25^{4}$ = 0.3903

(d) Probability that more than 10 of the problems can be resolved today is

given by = P(X > 10)

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

= $\binom{15}{11}0.75^{11}(1-0.75)^{15-11}+\binom{15}{12}0.75^{12}(1-0.75)^{15-12} + \binom{15}{13}0.75^{13}(1-0.75)^{15-13}+\binom{15}{14}0.75^{14}(1-0.75)^{15-14} + \binom{15}{15}0.75^{15}(1-0.75)^{15-15}$

= $1365*0.75^{11} *0.25^{4} + 455*0.75^{12} *0.25^{3}+105*0.75^{13} *0.25^{2} + 15*0.75^{14} *0.25^{1}+1*0.75^{15} *0.25^{0}$

= 0.6865

3 0

3 years ago

What is the relation between the variables in the equation x^4/y=7?

makkiz [27]

Answer:

So, the relation between variables are

$y=\frac{x^4}{7}$

Step-by-step explanation:

We are given

$\frac{x^4}{y}=7$

Since, we have to find relation between variables

so, we can solve for y

$\frac{x^4}{y}=7$

Firstly, we will multiply both sides by y

$\frac{x^4}{y}\times y=7\times y$

we can simplify it

$x^4=7\times y$

we can isolate y

so, we can divide both sides by 7

so, we get

$y=\frac{x^4}{7}$

8 0

3 years ago

22 is what percentage of 55%

Liula [17]

Answer:

12.1

Step-by-step explanation:

3 0

3 years ago

A pizza chain wants to send codes for $2 off a large pizza to the subscribers of its e-mail list. Each coupon code will have thr

kati45 [8]

Answer:

438,012 ways.

Step-by-step explanation:

We have been given that each coupon code will have three letters followed by two digits. The letters M, N, and O and the digits 1, 3, 5, and 7 will not be used. So, there are 23 letters and 6 digits that will be used.

Since the letters and digits can be repeated, so we will use fundamental principal of counting.

For first place, we can use 23 letters, for 2nd and 3rd place we can use 23 letters.

We can use 6 digits for 1st digit place and 6 digit for 2nd digit place as repetition is allowed.

So we can choose coupon code is following ways:

$23\cdot 23\cdot 23\cdot 6\cdot 6=438012$

Therefore, we can choose coupon codes in 438,012 ways.

3 0

3 years ago