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3 years ago

Which ordered pair would form a proportional relationship with the point graphed below?

Mathematics

1 answer:

Leviafan [203]3 years ago

8 0

(90.60)
This is the answer because i calculated it:) hope this helps!

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There are 7 tigers in a castle,each tiger has 7 children,each child has 7 tiger friends,then how many tigers are there in the ca

Ksenya-84 [330]

There are 7 parent tigers
Parents = 7

7 tigers each have 7 children. That means there's total of 7 × 7 children.
Children = 7 × 7 = 49

Each child has 7 friends. That means there's total of 49 × 7 friends.
Friends = 49 × 7 = 343

Total = 7 + 49 +343 = 399 TIGERS
I'm not a tiger so I'm not counting myself.

3 0

4 years ago

Whats the next five terms for 3,7,11,15

Rainbow [258]

Answer:

19,23,27,31,35

Step-by-step explanation:

It's going up by 4 each time.

6 0

3 years ago

Read 2 more answers

Find the distance between the two points rounding to the nearest tenth (if necessary). (-1,8) and (8,5)

Cloud [144]

Your answer to is 9.5

4 0

3 years ago

Solve the system of equations:x + 3y - z = -4 2x - y + 2z = 13 3x - 2y - z = -9

tatiyna

Answer:

The solution to the system of equations is

$\begin{gathered} x=\frac{179}{13} \\ \\ y=-\frac{279}{39} \\ \\ z=-\frac{48}{13} \end{gathered}$

Explanation:

Giving the system of equations:

$\begin{gathered} x+3y-z=-4\ldots\ldots\ldots\ldots\ldots\ldots..........\ldots\ldots\ldots\ldots.\ldots\text{.}\mathrm{}(1) \\ 2x-y+2z=13\ldots\ldots...\ldots\ldots\ldots\ldots..\ldots..\ldots\ldots\ldots\ldots\ldots.(2) \\ 3x-2y-z=-9\ldots\ldots\ldots.\ldots\ldots\ldots\ldots....\ldots\ldots.\ldots\ldots\ldots\text{.}\mathrm{}(3) \end{gathered}$

To solve this, we need to first of all eliminate one variable from any two of the equations.

Subtracting (2) from twice of (1), we have:

$5y-4z=-21\ldots\ldots\ldots\ldots\ldots.\ldots.\ldots..\ldots..\ldots\ldots.\ldots..\ldots\text{...}\mathrm{}(4)$

Subtracting (3) from 3 times (1), we have

$3y-5z=-3\ldots\ldots...\ldots\ldots..\ldots\ldots\ldots\ldots\ldots.\ldots\ldots\ldots\ldots\ldots..\ldots\ldots(5)$

From (4) and (5), we can solve for y and z.

Subtract 5 times (5) from 3 times (4)

$\begin{gathered} 13z=-48 \\ \\ z=-\frac{48}{13} \end{gathered}$

Using the value of z obtained in (5), we have

$\begin{gathered} 3y-5(-\frac{48}{13})=-3 \\ \\ 3y+\frac{240}{13}=-3 \\ \\ 3y=-3-\frac{240}{13} \\ \\ 3y=-\frac{279}{13} \\ \\ y=-\frac{279}{39} \end{gathered}$

Using the values obtained for y and z in (1), we have

$\begin{gathered} x+3(-\frac{279}{39})-(-\frac{48}{13})=-4 \\ \\ x-\frac{279}{13}+\frac{48}{13}=-4 \\ \\ x-\frac{231}{13}=-4 \\ \\ x=-4+\frac{231}{13} \\ \\ x=\frac{179}{13} \end{gathered}$

8 0

1 year ago

????????????????????????1

Rashid [163]

The answer should be C

8 0

3 years ago