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insens350 [35]
3 years ago
8

Whats the next five terms for 3,7,11,15​

Mathematics
2 answers:
Rainbow [258]3 years ago
6 0

Answer:

19,23,27,31,35

Step-by-step explanation:

It's going up by 4 each time.

Yuri [45]3 years ago
5 0
19, 23, 27, 31, 35 because it is going up by 4
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Fiona divided 3x2 5x – 3 by 3x 2. the expression represents the remainder over the divisor.what is the value of a?
Pavel [41]
If Fiona is to divide the first expression by the second one, clearly only the first term of the first expression is divisible. The remaining terms of the fist expression will remain as the remainder. The remainder from the division done by Fiona should be 5x - 3. 
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4 years ago
Vint is testing ceiling fans in a factory. For one of the tests, he switches the fan on, and after it attains a maximum speed of
Gennadij [26K]

Answer:

C. 20 seconds

Step-by-step explanation:

We want to know when y=0

The first y is when it started and the second y=0 is when it stops

Looking at the graph y=0 at x=0 and  y=0 at x=20

The fan started at time 0 and stopped at 20 seconds

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3 years ago
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In brianna's homeroom class, 9% of the students were born in march and 40% of the students have a blood type of o+.
Firlakuza [10]

Answer:

3.6%

Step-by-step explanation:

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3 0
2 years ago
Help!! (You will get 100 points! & Brainliest if you are correct)
Dafna1 [17]

Answer: The first number that appears in both sequences is 28.

Step-by-step explanation:

Let's write down numbers from each of the sequences

Sequence 1) We need to start from 7 and multiply 4

7x4=28, 28x4=112

The sequence is 7,28,112...

Sequence 2) We need to start from 8 and add 5

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The sequence is 8,13,18,23,28...

They both have 28

5 0
2 years ago
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2 tan 30°<br>II<br>1 + tan- 300​
shusha [124]

Question:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Answer:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

Step-by-step explanation:

Given

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Required

Simplify

In trigonometry:

tan(30^{\circ}) = \frac{1}{\sqrt{3}}

So, the expression becomes:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}

Simplify the denominator

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}

Express the fraction as:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= \frac{2}{\sqrt 3} / \frac{4}{3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2}{\sqrt 3} * \frac{3}{4}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{1}{\sqrt 3} * \frac{3}{2}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3}

Rationalize

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3\sqrt{3}}{2* 3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\sqrt{3}}{2}

In trigonometry:

sin(60^{\circ}) =  \frac{\sqrt{3}}{2}

Hence:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

3 0
3 years ago
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