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3 years ago

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You are arranging 7 books in a row on a shelf. one of the books is a dictionary and must go in the middle. how many ways can the

books be arranged?

1 answer:

alex41 [277]3 years ago

8 0

The other 6 books can be arranged in 6 ways

= 6*5*4*3*2*1 = 720 ways answer

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Please i need help urgently!!!

gladu [14]

Answer:

I'm pretty sure that it's just the negatives of the coordinates, (-3,-4) (-3,-1) (-5,-1). I don't know for sure tho, sorry if its wrong.

Step-by-step explanation:

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2 years ago

If you want to place a 9 3/4inch towel bar in the center of a door that is 27 1/2 wide how much faith will be on the each side o

vlada-n [284]

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3 years ago

Using the discriminant, how many real number solutions does this equation have? 3x^2 – 2 = 5x

Anvisha [2.4K]

The discriminant of this equation is 49. The solutions for this equation are x=2 and x=- $\frac{1}{3}$
I hope that helps.

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3 years ago

13.79-x for x=2.54<br> What is the answer

schepotkina [342]

Answer:

11.25

Step-by-step explanation:

13.79-x

Let x= 2.54

13.79-2.54

11.25

3 0

3 years ago

Read 2 more answers

Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.

Hitman42 [59]

$\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}
$

7 0

3 years ago