Answer:
2
Step-by-step explanation:
To find the scale of dilation, you have to compare the ratio of the after transform with before transform according to the center of dilation. In this case, the center of dilation is Q so you have to compare QA' : QA. We know that QA= 1.25 and AA' is 1.25. The distance of QA' will be:
QA'= QA + AA'= 1.25 + 1.25 = 2.5
The scale factor will be:
scale factor= QA' : QA.= 2.5 : 1.25
scale factor= 2
A. It is 176^2 or 30976 or 3.0976 x 10^4 whatever your prefer
B. 972
C. It is 0.00548697 or 4/729 or (2/27)^2 whatever your prefer
D. It is -16 x 20^4 or -2560000 whatever your prefer
E. x^4 y^4
F. h^10 k^6
G. m^11 n^15
H. b^2 d^6
....,,,,,,, you welcome !!!!!! :)
Answer:
See explanation below
<u>Step-by-step explanation:</u>
range = 2200 - 300 = 1900
To find standard deviation, we have:
standard deviation = range/4 = 
= 475
The range rule of thumb estimate for the standard deviation is 475
Given:
Standard deviation,
= 475
Margin of Error, ME = 100
= 1 - 0.90 = 0.10
Za/2 = Z0.05 = 1.64
Find sample size, n:
n ≥ ![[Z_\alpha_/_2 * (\frac{\sigma}{ME})]^2](https://tex.z-dn.net/?f=%20%5BZ_%5Calpha_%2F_2%20%2A%20%28%5Cfrac%7B%5Csigma%7D%7BME%7D%29%5D%5E2%20)
n ≥ ![[1.64 * (\frac{475}{100})]^2](https://tex.z-dn.net/?f=%5B1.64%20%2A%20%28%5Cfrac%7B475%7D%7B100%7D%29%5D%5E2)
n ≥ 60.68
≈ 61
Minimun sample size,n = 61
Answer:
Step-by-step explanation:
I say seven...
