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tamaranim1 [39]
3 years ago
13

I NEED HELP PLZ I WILL GIVE THANKS AND BRAINLIST

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

His test IS a solution.

Step-by-step explanation:

Both LHS and RHS are equal so it is a solution.

bija089 [108]3 years ago
7 0

I think that (His test point is a solution) is the answer

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PLS EXPLAIN HOW THESE SEQUNCE IS FORMED<br><br>ALL ODD NUMBERS
scoundrel [369]

Answer:

7,21,27,81,87, 261, 267....

Step-by-step explanation:

All odd number series from the given figure is

7, 21, 27, 81 , 87....

We can write this series as

7, 7 x 3 , (7x3)+6, ((7x3)+6)x3, (((7x3)+6)x3)+6....

7, 21, 21+6 , 27 x 3, 81+6...

Now, the next term of the series will be

=((((7x3)+6)x3)+6) x 3

= 87 x 3

= 261

And another term of the series will be

= 261 +6

= 267

7,21,27,81,87, 261, 267....

8 0
3 years ago
Find the product or quotient of 60÷12=?
Alexxandr [17]
Your answers is for sure 5
3 0
3 years ago
Read 2 more answers
What is the end behavior of this radical? f(x) = 4 square root x - 6
Tanzania [10]

Answer:

I think you can answer it with a chart, I guess, of course I'm not sure‍♀️

8 0
3 years ago
If the mean of a positively skewed distribution is 122, which of these values could be the median of the distribution?
frosja888 [35]

In a positively skewed distribution, the extreme scores are larger, thus the mean is larger than the median. Since the mean is 122, the only possible median is 118. Therefore, D.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
8 0
3 years ago
Read 2 more answers
A standard deck of 52 cards has 13 ranks (Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King) and 4 suits ($\spadesuit$, $\heart
Furkat [3]

Answer:

4 / 663

Step-by-step explanation:

Given that :

Number of cards in a standard deck = 52

Number of 3's in s standard deck = 4 (each suit has one card each)

Number of 8's in a standard deck = 4 (each suit has one card each)

Probability, P = required outcome / Total possible outcomes

Choosing without replacement :

P(top card is a 3) = 4 / 52

P(second draw is 8) = 4 / 51

P(top card is a 3 and second is 8) :.

4/52 * 4/51 = 16 / 2652 = 4 / 663

6 0
3 years ago
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