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likoan [24]
3 years ago
7

What is the missing side length?

Mathematics
1 answer:
Leokris [45]3 years ago
3 0

Step-by-step explanation:

the missing side length is 6..........

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In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
Please help. I need to raise my grade!
scoundrel [369]
The answer is the last one 7/8 x -3/4 =6
7 0
3 years ago
r=35.7+1.37t The equation above relates the urbanization rate r, as a percent, in a particular country to the number of years t
Lubov Fominskaja [6]

Answer: 37.07

because 35.7+1.37 is 37.07

5 0
3 years ago
An outlet store receives a shipment of sets of bunk beds that will be offered at a discounted price of $160 apiece. The sets of
GrogVix [38]

Answer:

17.1%

Step-by-step explanation:

160/193=0.829

1-0.829=0.171

Move the decimal place over two places, and the answer is 17.1%

4 0
3 years ago
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I miss 3 out of 10 questions on a health quiz. What is the percentage of correct answers???
Vladimir79 [104]
So 10 questions is 100% you missed 30% of the questions so you would do 100%-30% which is 70%
8 0
3 years ago
Read 2 more answers
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