Plz help i give brainlist fdf sfdfs fsdfdsfferw5tah3bgsewr35hatb
Bx%7D%20%5Csqrt%5Bn%5D%7Bx%7D%20%5Cpi%20%5Calpha" id="TexFormula1" title="x^{2} \sqrt[n]{x} \sqrt[n]{x} \pi \alpha" alt="x^{2} \sqrt[n]{x} \sqrt[n]{x} \pi \alpha" align="absmiddle" class="latex-formula">
2 answers:
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1. Check the picture attached.
let P, M, N be the points :P(5, -2), M(5, 0), N(0, -2)
ABP is the angle with measure ∅, where BA is the initial ray and BP the terminal ray.
2. m(PNM)=∅ as can be easily checked
In triangle PNM, NP=5, PM=2 and NM=
units
3. let opp=opposite side, adj=adjecent side, hyp=hypothenuse
sin ∅ = opp/hyp=
cos ∅ = adj/hyp=
tan ∅ = opp/adj=2/5
cot ∅ = adj/opp=5/2
sec ∅ = hyp/adj=
csc ∅ = hyp/opp=
let P, M, N be the points :P(5, -2), M(5, 0), N(0, -2)
ABP is the angle with measure ∅, where BA is the initial ray and BP the terminal ray.
2. m(PNM)=∅ as can be easily checked
In triangle PNM, NP=5, PM=2 and NM=
3. let opp=opposite side, adj=adjecent side, hyp=hypothenuse
sin ∅ = opp/hyp=
cos ∅ = adj/hyp=
tan ∅ = opp/adj=2/5
cot ∅ = adj/opp=5/2
sec ∅ = hyp/adj=
csc ∅ = hyp/opp=