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Viktor [21]
3 years ago
15

Plz help i give brainlist fdf sfdfs fsdfdsfferw5tah3bgsewr35hatb

Bx%7D%20%5Csqrt%5Bn%5D%7Bx%7D%20%5Cpi%20%5Calpha" id="TexFormula1" title="x^{2} \sqrt[n]{x} \sqrt[n]{x} \pi \alpha" alt="x^{2} \sqrt[n]{x} \sqrt[n]{x} \pi \alpha" align="absmiddle" class="latex-formula">

Mathematics
2 answers:
svetoff [14.1K]3 years ago
6 0
What’s the question
kvasek [131]3 years ago
3 0
What so you want done with these numbers?
You might be interested in
If pentagon ABCDE is rotated 180 degrees around the origin to create pentagon A’ B’ C’ D’ E’, what is the ordered pair of point
Naddik [55]
You haven't provided the original coordinates or the figure, therefore, I cannot give an exact answer. However, I will help you with the concept.

For rotation 180° about the origin, the signs of both the x any y coordinates are changed.
<u>This can be modeled as follows:</u>
(x,y) ......> rotation 180° about the origin ........> (-x,-y)

<u>Examples:</u>
(1,2) .......> rotation 180° about the origin ........> (-1,-2)
(2,-19) ....> rotation 180° about the origin ........> (-2,19)
(-3,-8) .....> rotation 180° about the origin ........> (3,8)
(-5,7) ......> rotation 180° about the origin ........> (5,-7)

Based on the above, all you have to do to get the coordinates of C' is change the signs of both the x and y coordinates

Hope this helps :)

5 0
3 years ago
NEED HELP!!!!!!!!!!!!!!!!! Math problem! Please help!
Elanso [62]

Answer:

You are correct, it is C.

8 0
3 years ago
Find the shortest distance, d, from the point (5, 0, −6) to the plane x + y + z = 6.
DENIUS [597]

Answer:

\frac{7}{\sqrt{3}}

Step-by-step explanation:

The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:

d = |\frac{(ma + nb + tc - r)}{\sqrt{m^2 + n^2 + t^2}} |                   --------------------(i)

From the question,

the point is (5, 0, -6)

the plane is x + y + z = 6

Therefore,

a = 5

b = 0

c = -6

m = 1

n = 1

t = 1

r = 6

Substitute these values into equation (i) as follows;

d = |\frac{((1*5) + (1*0) + (1 * (-6)) - 6)}{\sqrt{1^2 + 1^2 + 1^2}} |

d = |\frac{((5) + (0) + (-6) - 6)}{\sqrt{1 + 1 + 1}} |

d = |\frac{(-7)}{\sqrt{3}} |

d = \frac{7}{\sqrt{3}}

Therefore, the shortest distance from the point to the plane is  d = \frac{7}{\sqrt{3}}

5 0
3 years ago
Can someone help me plz
Musya8 [376]

Answer:

B

Step-by-step explanation:

lets say the cost for a pound is 2$

if the watermelon weighs 3 pounds it would cost $6.

2(3)

The weight is the variable in the parenthesis because that is what is constantly changing.

4 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST
Svetach [21]

Answer:

Check explanation

Step-by-step explanation:

I'll give you my way of solving it and you can figure it out from there.

<CEA = <DEB due to vertical angles

AE = ED due to midpoint theorem

<CAD = <ADB due to alternating angles theorem

thus two triangles congruent due to ASA

5 0
3 years ago
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