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3 years ago

H(n) = -n^2+4+n g(n) = n-1 Find g(h(n))

Mathematics

1 answer:

jasenka [17]3 years ago

4 0

Answer:

H(n) = -n^2+4+n

g(n) = n-1

Find g(h(n))

Step-by-step explanation:

hello :

g(h(n)) = g(-n²+4+n) =(-n²+4+n)-1

g(h(n)) =-n²+n+3

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Jobisdone [24]

ANSWER

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2 years ago

Prove algebraically that r = 10/2+2sinTheta is a parabola

Xelga [282]

Answer:

$y = - \frac{ 1 }{10} {x}^{2} + \frac{5}{2}$

Step-by-step explanation:

We want to prove algebraically that:

$r = \frac{10}{2 + 2 \sin \theta}$

is a parabola.

We use the relations

${r}^{2} = {x}^{2} + {y}^{2}$

and

$y = r \sin \theta$

Before we substitute, let us rewrite the equation to get:

$r(2 + 2 \sin \theta) = 10$

$r(1+ \sin \theta) = 5$

Expand :

$r+ r\sin \theta= 5$

We now substitute to get:

$\sqrt{ {x}^{2} + {y}^{2} } + y = 5$

This means that:

$\sqrt{ {x}^{2} + {y}^{2} }=5 - y$

Square:

${x}^{2} + {y}^{2} =(5 - y)^{2}$

Expand:

${x}^{2} + {y}^{2} =25 - 10y + {y}^{2}$

${x}^{2} =25 - 10y$

${x}^{2} - 25 = - 10y$

$y = - \frac{ {x}^{2} }{10} + \frac{5}{2}$

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2 years ago

An item is regularly priced at $45 . it is on sale for 60% off the regular price. how much (in dollars) is discounted from the r

wariber [46]

The discount is 60% of regular price, or we can write it as
discount = 60% × regular price

input the numbers
discount = 60% × regular price
discount = 60% × 45
discount = 60/100 × 45
discount = 2,700/100
discount = 27

The answer is $27

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3 years ago

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Answer:

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2 years ago

Read 2 more answers

Please help solve questions

Alekssandra [29.7K]

Take some points