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Valentin [98]
3 years ago
5

H(n) = -n^2+4+n g(n) = n-1 Find g(h(n))

Mathematics
1 answer:
jasenka [17]3 years ago
4 0

Answer:

H(n) = -n^2+4+n

g(n) = n-1

Find g(h(n))

Step-by-step explanation:

hello :

g(h(n)) = g(-n²+4+n) =(-n²+4+n)-1

g(h(n)) =-n²+n+3

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Help me i dont really understand
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Answer:

73

Step-by-step explanation:

12(6) + 1/4 • 2^2

Square the 2 first.

12(6) + 1/4 • 4

Then multiply from left to right.

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Lastly, add.

73

The parenthesis around the 6 mean multiplication, not the Parenthesis that are grouping symbols if you are learning PEMDAS. So your question has no grouping symbol parenthesis. Next comes Exponents, that's why we squared the 2. Multiply and Divide come next IN THE ORDER THAT THEY APPEAR FROM LEFT TO RIGHT. Then the same method with adding and subtracting. That's called the order of operations.

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3 years ago
Jessica can walk 1.5 kilometers in 30 minutes. How long will it take her to walk 2.5 kilometers?
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Answer:

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Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
What is the standard form equation of the line shown below?
ch4aika [34]
(-1,1)(1,4)
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y = mx + b
slope(m) = 3/2
use either of ur points....(1,4)...x = 1 and y = 4
now sub and find b, the y int
4 = 3/2(1) + b
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equation is y = 3/2x + 5/2...but we need it in standard form

y = 3/2x + 5/2
-3/2x + y = 5/2.....multiply both sides by -2
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3 years ago
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