3 years ago

H(n) = -n^2+4+n g(n) = n-1 Find g(h(n))

Mathematics

1 answer:

jasenka [17]3 years ago

4 0

Answer:

H(n) = -n^2+4+n

g(n) = n-1

Find g(h(n))

Step-by-step explanation:

hello :

g(h(n)) = g(-n²+4+n) =(-n²+4+n)-1

g(h(n)) =-n²+n+3

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