Answer:
a straight line that does not go through the origin.
Answer: AC=12 cm
Step-by-step explanation:
To solve this problem you must apply the law of sines, as you can see below:
![\frac{a}{sinA}=\frac{b}{sinB}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7BsinA%7D%3D%5Cfrac%7Bb%7D%7BsinB%7D)
Where:
a=13
A=85.2°
B=71.6°
Therefore, you must solve for b, then, you obtain that the lenght AC asked in the problem above is:
![b={sinB}*\frac{a}{sinA}\\b=\frac{sin(71.6)*13}{sin(85.2)}\\b=12](https://tex.z-dn.net/?f=b%3D%7BsinB%7D%2A%5Cfrac%7Ba%7D%7BsinA%7D%5C%5Cb%3D%5Cfrac%7Bsin%2871.6%29%2A13%7D%7Bsin%2885.2%29%7D%5C%5Cb%3D12)
Answer:
the answer to 30-60-90=0
Step-by-step explanation:
90-60=30-30=0
A) The longest horizontal distance is reached at 45 degrees angle. This is true for any projectile launch.
B) First, calculate fligth time (using the vertical motion) and then calculate the horizontal movement.
Flight time = 2* ascendent time
ascendent time => final vertical velocity, Vy, = 0
sin(45) = Voy / Vo => Voy = Vosin(45) = 25.5 m/s * (√2) / 2 = 18.03 m/s
Vy = Voy - gt = 0 => Voy = gt = t = Voy / g
Use g = 10 m/s^ (it is an aproximation, because the actual value is about 9.81 m/s^2 depending on the latitud)
t = 18.03 m/s / 10 m/s^2 = 1.83 s
This is the ascendant time going upward.
The flight time is 2*1.83 = 3.66 s
Horizontal motion
Horizontal velocity = Vx = constant = Vox = Vo*cos(45) = 18.03 m/s
Vx = x / t => x = Vx*t
Horizontal distance = xmax = 18.03m/s*3.66 s = 65.99 m
c) The time the ballon will be in the air was calculated in the part B, it is 18.03 s
Answer:
5 times 5 24
Step-by-step explanation: