3 years ago

Can you help me with the 2 questions please help!!!

Mathematics

1 answer:

ollegr [7]3 years ago

6 0

Answer:

$\frac{17x^{3} }{30}$
$\frac{x^{4} }{9}$

I hope this helps!

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6. The first six terms in a quadratic pattern are

dexar [7]

Since 83-59=24, 83 is added by 28 so your answer would be 111.

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3 years ago

Which are differences of perfect cubes? Select two options

schepotkina [342]

Answer: The last 3 choices

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2 years ago

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PLZZZZZZ NEED HELP!!!!!!!

fredd [130]

Answer:

angle B=120º

Step-by-step explanation:

15+45=60

We know that all triangles have angle measures that equal 180

So 180-60=120

angle B=120º

7 0

3 years ago

What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?

Akimi4 [234]

$\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------$

$\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5$

4 0

2 years ago

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How many Erving of 3/4 cup of beans are in half a cup?

jenyasd209 [6]

Well a half cup is 2/4 and if the serving size is 3/4 there is only 66.66% of the serving size needed hope this helps!

7 0

3 years ago

Can you help me with the 2 questions please help!!!​

Can you help me with the 2 questions please help!!!