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inna [77]
3 years ago
13

Find f(-3) when f(x) = -x2 + 1 A) -10 B) -8 C) 7 D) 8

Mathematics
1 answer:
Degger [83]3 years ago
3 0

Answer:

f(-3) = -8

Step-by-step explanation:

  1. f(-3) = - x^2 + 1
  2. f(-3) = - (-3)^2 + 1
  3. f(-3) = - (9) + 1
  4. f(-3) = - 9 + 1
  5. f(-3) = -8
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3 years ago
Martin earned the following scores on his last five tests.
egoroff_w [7]
<span>98, 78 , 84, 75, 91
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The interquartile range formula is the first <span>quartile </span>subtracted from the third quartile:

<span>IQR = Q3 – Q1.</span>

<span><span>****************************************************
Step 1: Put the numbers in order.
75, 78, 84, 91, 98

</span><span><span>Step 2: </span><span>Find the median</span>.
</span></span>75, 78, 84, 91, 98
<span>
<span><span>Step 3: </span><span>Place parentheses around the numbers above and below the median. </span>
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
</span></span>(75, 78), 84, (91, 98)
<span>
<span><span>Step 4: </span>Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
</span></span>(75, 78), 84, (91, 98)

<span>*(75, 78) ---> (75 + 78) </span>÷ 2 = 76.5
<span>*(91, 98) ---> (91 + 98) </span>÷ 2 = 94.5
<span>
<span><span>Step 5: </span>Subtract Q1 from Q3 to find the interquartile range.
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7 0
3 years ago
Read 2 more answers
a building with a height of 32m casts a shadow that is 20m long. a person standing casts a shadow that is 1.2 m long how tall is
wlad13 [49]
Most of the information's required for solving the question is already given in the question.
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Then
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So the actual height of the person casting a shadow of 1.2 meter is 3.84 meters. I hope that the procedure used for solving the problem is easy enough for you to understand. You can definitely use this method in future for solving problems of similar type without requiring any additional help from outside.

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4 years ago
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