Answer:
Step-by-step explanation:
The total number of sums (not distinct) is 
, because we're removing without replacement.
Count the sums that fit the stipulation (sum 
5):
There are 8 sums that work. Therefore, the desired answer is 
Let's assume
It started in 2000
so, t=0 in 2000
we can use formula
we can plug value
In 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million
so, at t=2005-2000=5
P(t)=7.3 million
we can plug value and then we can solve for r
now, we can plug back
now, we have
P(t)=1 billion =1000 million
so, we can set it and then we can solve for t
approximately
Year is 2000+192
year is 2192................Answer
Answer: $3,166
Step-by-step explanation:
Answer:
You will need 20 sides to complete the loop.
Step-by-step explanation:
The question isn't quite clear given how small the corner is, but I assume that we are looking to complete the circle if the pentagon and square are repeated in a loop
We can also see - assuming that those are proper equal-sided polygons, that PQ is the same length as PV
With that in mind, We can solve this by noting that the angle of a corner in a square is 90 degrees, and in a pentagon it's 108 degrees.
108 - 90 is equal to 18. This means that PQ is at eighteen degrees to YP. Also, QM, (which will be equivalent to the next VP is eighteen degrees to PQ.
This means that each polygon is rotated 18 degrees relative to it's neighbour.
With all that we can say that the total polygons we need to form a circle is 360/18 = 20, So you will need 20 polygons, or ten squares and ten pentagons to complete the loop.
