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Archy [21]
3 years ago
13

Evaluate (f *g)(x) if f(x) = 2x^2 and g(x) = 3x – 2.

Mathematics
2 answers:
Oksanka [162]3 years ago
5 0

Answer:

6x^3 - 4x^2

Step-by-step explanation:

f(x) = 2x^2 and g(x) = 3x – 2

(f*g) (x) =  2x^2 * (3x-2)

           = 6x^3 - 4x^2

V125BC [204]3 years ago
5 0

Answer:

6x^3 - 4x^2

Step-by-step explanation:

(f*g)(x)

(2x^2)(3x-2)(x)

(6x^3 - 4x^2)(x)

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Since a(2)=0, we know that t-2 must be a factor of a(t), so k=2. Then the zeros of a(t) are t=2,3,6,-3, and their product is -108, whose absolute value is 108.

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Sally has 50 pencils. 38% of them have stripes. How many have stripes?
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Step-by-step explanation:

7 0
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Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
Gennadij [26K]

Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

  • Minimum value is 19.
  • Maximum value is of 134.
  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

6 0
3 years ago
while shopping, betting spent five times as much as meg. if they spent a total of $108, how much did each person spend?
yulyashka [42]

Answer:

meg spen $18 and betting spent $90

Step-by-step explanation:

5 0
2 years ago
9mph in still water it takes 5hrs longer to travel 74 miles upstream than downstream find the rate of current and round to neare
prohojiy [21]

Answer:

The rate of current is 2.5 mph.

Step-by-step explanation:

The speed in the water when current is absent is 9 mph.

If the speed of the current is v mph then the upstream speed is (9 - v) mph and the downstream speed is (9 + v) mph.

Now, it takes 5 hours longer to travel 74 miles upstream than down stream, then we can write the equation as  

\frac{74}{9 - v} - \frac{74}{9 + v} = 5

⇒ \frac{2v}{81 - v^{2} } = \frac{5}{74}

⇒ 148v = 405 - 5v²

⇒ 5v² + 148v - 405 = 0

Applying Sridhar Acharya's formula we can write  

v = \frac{-148 + \sqrt{148^{2} - 4(5)(-405) }  }{2(5)} (Neglecting the negative root)

⇒ v = \frac{- 148 + 173.2166}{10} = 2.5 mph (Rounded to the nearest 10th) (Answer)

7 0
3 years ago
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