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Alisiya [41]
3 years ago
11

3(5-2h)+9=-30 I need to find h

Mathematics
2 answers:
Mkey [24]3 years ago
3 0
3(5-2h)+9=-30
15-6h+9=-30
24-6h=-30
-6h=-54
h= 9
skad [1K]3 years ago
3 0
<span>3(5-2h)+9=-30
Multiply the number outside of the parenthesis with the numbers inside the parenthesis
15-6h+9=-30
Subtract 15 from both sides
-6h+9=-45
Subtract 9 from both sides
-6h=-54
Divide -6 on both sides
Final Answer: 9</span>
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5x – 4y = 9<br> x - 2y = 3 <br> System of equation
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A wallet contains $460 in $5, $10, and $20 bills. The number of $5 bills exceeds twice the number of $10 bills by 4, and the num
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Answer:

Number of $5 bills = 32

Number of $10 bills = 14

Number of $20 bills = 8

Step-by-step explanation:

Let x number of $5, y number of $10 and z number of $20

The number of $5 bills exceeds twice the number of $10 bills by 4.

Therefore, x = 2y + 4

The number of $20 bills is 6 fewer than the number of $10 bills.

Therefore, z = y - 6

A wallet contains $460 in $5, $10, and $20 bills.

Therefore,

5x + 10y + 20z = 460

Substitute x and y into equation

    5(2y+4) + 10y + 20(y-6) = 460

10y + 20 + 10y + 20y - 120 = 460

                           40y - 100 = 460

                                    40y = 460 + 100

                                    40y = 560

                                      y = 14

  • Put the value of y into x = 2y + 4 and solve for x

                                      x = 2(14) + 4

                                      x = 32

  • Put the value of y into z = y - 6 and solve for z

                                      z = 14 - 6

                                      z = 8

Hence, the each type of bills,

Number of $5 bills = 32

Number of $10 bills = 14

Number of $20 bills = 8

3 0
3 years ago
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