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igor_vitrenko [27]
3 years ago
7

What is the slope of the line in this graph?

Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
8 0

Answer:

5/9

Step-by-step explanation:

You got to find 2 points that you want and use the formula y1-y2 and x1=x2 and you find your slope.

Furkat [3]3 years ago
5 0

Answer:

b: 5/7

Step-by-step explanation:

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Which answer shows a reflection across the x-axis?<br> A B C D
Ivahew [28]

Answer:

C is the correct answer

Step-by-step explanation:

Reflection kinda means like a mirror across the x-axis

in the picture below i labeled the x-axis's and cirlced the answer as well

sorry its not the best drawing but i tried

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3 years ago
I’m trying to find tan B
emmasim [6.3K]
15/8 is your answer, i hope i’m right
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4 years ago
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What is the solution to the inequality |2n+5|&gt;1?
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C is the correct answer.<span />
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3 years ago
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Mr Rai sale a watch for Rs 2035 a profit of 10% how much money has he paid to buy the also find his profit amount​
Firdavs [7]

Answer:

He paid Rs 1,850 to buy the watch

Profit = Rs 185

Step-by-step explanation:

Cost price = x

Profit = 10% of x

Selling price = Rs 2035

Profit = Selling price - cost price

10% of x = 2035 - x

0.1x = 2035 - x

0.1x + x = 2035

1.1x = 2035

x = 2035 / 1.1

x = 1,850

Cost price = x = Rs 1,850

Profit = 10% of x

= 10% of 1,850

= 0.1 × 1850

= 185

Profit = Rs 185

5 0
3 years ago
Consider xưy" – 14xy' + 56y = 0. Find all values of r such that y=x" satisfies the differential equation for x &gt; 0. Enter as
beks73 [17]

I bet the ODE is supposed to read

x^2y''-14xy'+56y=0

Then if y=x^r, we have y'=rx^{r-1} and y''=r(r-1)x^{r-2}, and substituting these into the ODE gives

r(r-1)x^r-14rx^r+56x^r=0\implies r(r-1)-14r+56=r^2-15r+56=0

Solving for <em>r</em>, we find

r^2-15r+56=(r-8)(r-7)=0\implies \boxed{r=8\text{ or }r=7}

so that y_1=x^8 and y_2=x^7 are two fundamental solutions to the ODE. Thus the general solution is

\boxed{y(x)=C_1x^8+C_2x^7}

Given that y(1)=4 and y'(1)=3, we get

\begin{cases}4=C_1+C_2\\3=8C_1+7C_2\end{cases}\implies C_1=-25\text{ and }C_2=29

So the particular solution is

\boxed{y(x)=29x^7-25x^8}

4 0
4 years ago
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