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3 years ago

10

Urgent!! Math!! What’s the answer to 1,2,3?

1 answer:

KiRa [710]3 years ago

8 0

Answer:

1. x=8 2. x=

Step-by-step explanation:

1. 17^2-15^2= 64

=8

x=8

sorry i only know 1

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Someone help me please

Gemiola [76]

Answer:

$x=2\sqrt{6}$

Step-by-step explanation:

Use the Pythagorean theorem:

$a^2+b^2=c^2$

a and b are the legs and c is the hypotenuse. Insert the values:

$\sqrt{10}^2+\sqrt{14}^2=x^2$

Simplify exponents using the rule $\sqrt{x}^2=x$ :

$10+14=x^2$

Simplify addition:

$24=x^2\\x^2=24$

Find the square root:

$\sqrt{x^2}=\sqrt{24}\\ x=\sqrt{24}$

Simplify in radical form: Find a common factor of 24 that is a perfect square:

$\sqrt{24}=\sqrt{4*6}$

Separate:

$\sqrt{4}*\sqrt{6}$

Simplify:

$2*\sqrt{6}\\x=2\sqrt{6}$

Finito.

3 0

3 years ago

Read 2 more answers

20=10-2y+4+4y what does y equal

Mila [183]

Answer:

y = 3

Step-by-step explanation:

$10-2y+4+4y+20$

Combine like terms

$2y+14=20$

Move all terms not containing y to the right side of the equation.

$2y=6$

Divide both sides by 2

y = 3

Plz mark me brainliest!

It's ok if u don't...lol

I hope this helped!!

4 0

3 years ago

-18 + 2a = 2(3a + 1)

Nadusha1986 [10]

Answer:

a = -5

Step-by-step explanation:

Given

-18 + 2a = 2(3a + 1)

Expand the bracket on the right

-18 + 2a = 2 x 3a + 2 x 1

-18 + 2a = 6a + 2

Add 18 to both sides

-18 + 18 + 2a = 6a + 2 + 18

2a = 6a + 20

Subtract 6a from both sides

2a - 6a = 6a - 6a + 20

-4a = 20

Divide both sides by -4

-4a/-4 = 20/-4

a = -5

3 0

3 years ago

Suppose the population of a certain city is 3031 thousand. It is expected to decrease to 2246 thousand in 50 years. Find the per

Kipish [7]

Answer:

The rate at which the population decrease is 59.8 %

Step-by-step explanation:

Given as :

The population of city = 30,31,000

Now The population of city decrease to 22,46,000

The time period in which population decrease is 50 years

Let the percentage rate of decrease = R%

So,

Final population = initial population × $(1-\frac{Rate}{100})^{Time}$

Or, 22,46,000 = 30,31,000 × $(1-\frac{Rate}{100})^{50}$

Or, $\frac{2246000}{3031000}$ = $(1-\frac{Rate}{100})^{50}$

Or, $\frac{2246}{3031}$ = $(1-\frac{Rate}{100})^{50}$

$(\frac{2246}{3031})^{\frac{1}{50}}$ = $( 1-\frac{Rate}{100})$

So , 0.99402 = $( 1-\frac{Rate}{100})$

Or, $\frac{Rate}{100}$ = 1 - 0.99402

So, Rate = $5.98\times 10^{-3}$ × 100

Or, Rate = 0.598 = 59.8 %

Hence The rate at which the population decrease is 59.8 % Answer

4 0

3 years ago

Find Mx, My, and (x, y) for the lamina of uniform density rho bounded by the graphs of the equations. y = x2/3, y = 0, x = 1

erik [133]

Answer:

$\mathbf{(\overline x , \overline y ) = (\dfrac{5}{8}, \dfrac{5}{14})}$

Step-by-step explanation:

Given that:

$y = x^{2/3}$ at y = 0 , x = 1

Then:

Area = $\int^{1}_{0} x^{2/3} \ dx$

Area = $\begin {bmatrix} \dfrac{3}{5}x^{5/3} \end {bmatrix} ^1_0$

Area = $\dfrac{3}{5}$

Then:

$\overline x = \dfrac{1}{A} \int^b_a x (f(x) -g(x) ) \ dx$

$\overline x = \dfrac{5}{3} \int^1_0 x (x^{2/3} -0 ) \ dx$

$\overline x = \dfrac{5}{3} \int^1_0 x^{5/3} \ dx$

$\overline x = \dfrac{5}{3} \ [\dfrac{3}{8}x^{8/3}]^1_0$

$\overline x = \dfrac{5}{3} \times \dfrac{3}{8}$

$\overline x = \dfrac{5}{8}$

Similarly;

$\overline y = \dfrac{1}{A} \int^b_a \dfrac{1}{2} \begin{bmatrix} (f(x)^)2 - (g(x))^2 \end {bmatrix} \ dx$

$\overline y = \dfrac{5}{3} \int^1_0 \dfrac{1}{2} \begin{bmatrix} (f(x^{2/3})^2 -0 \end {bmatrix} \ dx$

$\overline y = \dfrac{5}{3} \int^1_0 \dfrac{1}{2} \begin{bmatrix} (x^{4/3} ) \end {bmatrix} \ dx$

$\overline y = \dfrac{5}{3} \begin{bmatrix} \dfrac{1}{2} (x^{7/3} ) \times \dfrac{3}{7} \end {bmatrix} ^1_0$

$\overline y = \dfrac{5}{3} \begin{bmatrix} \dfrac{3}{14} (x^{7/3} ) \end {bmatrix} ^1_0$

$\overline y = (\dfrac{5}{3} \times \dfrac{3}{14} )$

$\overline y = \dfrac{5}{14}$

Thus; $\mathbf{(\overline x , \overline y ) = (\dfrac{5}{8}, \dfrac{5}{14})}$

4 0

3 years ago